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IrinaVladis [17]
4 years ago
7

Please help! How many triangles can be constructed with angle measurements of 90, 45, and 50?

Mathematics
1 answer:
GenaCL600 [577]4 years ago
6 0
None because 90 + 45 + 50 = 185 and triangles cannot exceed the measurement of 180°

Hope this helps

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1/3×7=<br><br><br>2 2/3×9=<br><br>3 1/5÷8=
Mrac [35]
1/3×7= 7/3

2 2/3×9= 8/3 x 9 = 72/3 = 24

3 1/5÷8= (16/5 ) / 8 = 16/5 x 1/8 = 16/40 = 4/10 = 0.4
4 0
4 years ago
Read 2 more answers
Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
Fudgin [204]
7.50h + 0.20s + 40

variable : a letter subbed in for an unknown number : s and h
coefficient : the number multiplied by the variable : 7.50 and 0.20
constant : just a lone number, no variable attached : 40

Corrine works for 25 hrs and sells 300......h = 25, s = 300
7.50h + 0.20s + 40
7.50(25) + 0.20(300) + 40 =
187.50 + 60 + 40 =
287.50 <===

if she gets a raise and earns 9 per hr...
the coefficient would change from 7.50 per hr to 9.00 per hr. because her pay rate has changed.
the new equation would then be : 9h + 0.20s + 40
4 0
3 years ago
HELP PLEASE <br><br>WIll give BRAINLIEST​
Studentka2010 [4]

Answer:

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6 0
3 years ago
How many Solutions does this system have? (1 point)
mixas84 [53]

The given system of equation that is 2x+y=3 and 6x=9-3y has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison

\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}

To check how many solutions are there for system of equations a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0, we need to compare ratios of \frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}

In our case,  

a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3

a_{2}  = 6, b_{2} = 3,\text{ and }c_{2} = -9

\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}

As \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}, so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0
3 years ago
Identify the terms and factors :
Charra [1.4K]

refer the attachment for your answer

8 0
3 years ago
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