Answer:
the maximum energy available for pumping a mole of glucose into the cell = 3190J
Explanation:
The detailed steps and appropriate derivation from the Vant hoff Isotherm equation is as shown in the attachment.
Fluorine ions reacts with Hydrogen chloride to form more hydrogen fluoride.
Therefore, moles of HCl = 0.005 l × 0.01 M = 5 ×10^-5 moles
The initial moles of Hydrogen fluoride will be;
= 0.0126 M× 0.0250 = 0.00315 Moles
Moles of hydrogen fluoride after the addition of HCl
= 0.00315 + 5.0× 10^-5 = 0.0032 moles
Therefore, the concentration of Hydrogen chloride
= 0.0032 moles/ 0.030 L
= 0.107 M
Answer is in picture below.
Use 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; mass percentage of the chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; amount of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; amount of carbon.
n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.
This compound is dichlorocarbene CCl₂.
0.1324 ×10^24 atoms of carbon are in 2.65 g of carbon
Explanation:
Converting the grams of carbon to the moles of carbon.
Divide the mass (2.65 g) by 12.011 g/mol which is the molecular weight of carbon,
2.65 g / 12.011 g/mol=0.220 moles of carbon
Then, convert moles of carbon to atoms of carbon using Avogadro's constant (6.022×10^23 atoms per mole)
0.220 moles × 6.022×10^23 atoms / 1 mole = 0.1324 ×10^24 atoms
0.1324 ×10^24 atoms of carbon are in 2.65 g of carbon
Answer:
in order from left to right
1. continental crust.
2. fault
3. oceanic crust