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Kamila [148]
3 years ago
5

Molecules have Question 1 options: A) both potential and kinetic energy. B) neither kinetic nor potential energy. C) only kineti

c energy. D) only potential energy.
Chemistry
1 answer:
vfiekz [6]3 years ago
8 0

Answer:A

Explanation:

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A chemical reaction is shown below:
BabaBlast [244]

Answer:

Mass = 8.46 g

Explanation:

Given data:

Mass of water produced = ?

Mass of glucose = 20 g

Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

               C₆H₁₂O₆           :            H₂O

                   1                   :              6

                 0.11                :           6/1×0.11 = 0.66

                   O₂               :            H₂O

                   6                   :              6

                 0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

8 0
3 years ago
A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find
dalvyx [7]

Answer:

pOH= 14.248

[H+]=1.77 M

[OH-]=5.65 x10^-15M

Explanation:

pH+pOH= 14

pOH= 14-pH

pOH=14-(-0.248)

pOH= 14.248

[H+]=10^-pH= 10^-(-0.248)=1.77 M

[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

5 0
3 years ago
For the reaction C2H5OH + O2 --> 3CO2 + 3H2O
Lelechka [254]
The reaction given above is a combustion reaction. All combustion reactions are exothermic, meaning they give off heat when they react,
8 0
3 years ago
Proper significant figure: 27.01 + 14.369
Paul [167]

Answer:

<h2>put the bigger number on top then add </h2>

Explanation:

41.369

8 0
3 years ago
Calculate the percent by mass of carbon in CO2 (carbon dioxide). Please show all work.
anygoal [31]
%C= 12/12 + 2·16=0,273=27,3%.
6 0
3 years ago
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