Hannah places her home on a grid so that each unit square on the grid equates to 11 mile. She uses the fact that the major stree
ts in her town are located 11 mile apart and run at right angles to each other to place her school 55 miles south and 33 miles east of her home.
The distance from Hannah's home to her school, if that distance could be walked in a straight line, would be _____ miles.
Enter your answer as the number that correctly fills in the blank in the previous sentence.
Round your answer to one decimal place, if necessary, like this: 42.5
The distance from Hannah's home to her school, if that distance could be walked in a straight line, would be _____ miles.
Enter your answer as the number that correctly fills in the blank in the previous sentence.
Round your answer to one decimal place, if necessary, like this: 42.5
1 answer:
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Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form , where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:
Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.
Let us solve for n.
We can also write next terms of our sequence as:
Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.