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2 years ago

An executive is earning $45,000 per year. This is

1 answer:

4 0

Her salary 4 years ago would have been $30,000.

If 45,000 is 15,000 less than double her previous salary, we must first add 15,000 to 45,000 to find what double her salary was.

45,000+15,000=60,000.

Since this is twice her salary, we divide this by 2.

60,000/2= 30,000.

So, her salary 4 years ago would have been $30,000.

I hope this helps!

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A license plate consists of two letters followed by two digits; for example, $MP78$. Neither the digits nor the letters may be r

alex41 [277]

If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.

Given that a number plate can be formed using 2 alphabets which must come in increasing order.

We are required to find the number of plates that can be formed.

Number of total alphabets=26.

The number of plates will be equal to the number of ways in which two alphabets can be arranged.

Combination is the number of ways in which some combinations can be formed. It is expressed as n $C_{r}$ =n!/r!(n-r)!

Number of license plates=26 $C_{1}$ *25 $C_{1}$

=26*25

=650 plates

Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.

Learn more about combinations at brainly.com/question/11732255

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3 0

1 year ago

What is 4/2/3 x 1/3/7 ?

Tatiana [17]

Answer: 2/63

Step-by-

6 0

3 years ago

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the seed and skin of a typical avacado is about 30%-40% of the avocados weight. for an 8-ounce avocado, how many ounces of edibl

wolverine [178]

Answer:

Edible fruit amount is 4.8 ounce to 5.6 ounce

Step-by-step explanation:

Given as

The seed and skin of avocados is about 30%-40%

And the weight of avocados is 8 ounce

So, the weight of seed and skin is about 30% of 8 to 40% of 8

i.e 2.4 ounce to 3.2 ounce

Then the edible fruit is about 60% to 70%

i.e 60% of 8 to 70% of 8

Thus edible fruit of avocados = 4.8 ounce to 5.6 ounce Answer

5 0

3 years ago

If the weight of 7 sheets of paper is 35 grams, find how many sheets of paper it will take to weigh 1.5 kg

Leokris [45]

Answer:

300 sheets

Step-by-step explanation:

if you divide 35 by 7, you get 5

then divide 1,500 by 5 to get 300.

3 0

3 years ago

A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec

Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (n ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

$Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18$

The sample size is, n = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

$\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191$

(a)

The null hypothesis is:

H₀: The usual load is 13 credits, i.e. μ = 13.

Assume that the significance level of the test is, α = 0.05.

Construct a (1 - α) % confidence interval for population mean to check the claim.

The (1 - α) % confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\times SE$

For 5% level of significance the two tailed critical value of z is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct the 95% confidence interval as follows:

$CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)$

As the null value, μ = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

$P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z$

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

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2 years ago

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