Pls someone help please

Find the length of the third side.if necessary, round to the nearest tenth 24 18

VashaNatasha [74]

Answer:

30

Step-by-step explanation:

\text{Legs: 18, 24}\hspace{20px}\text{Hypotenuse: ?}

Legs: 18, 24Hypotenuse: ?

a^{2}+b^{2}=

a

2

+b

2

=

\,\,c^{2}

c

2

The Pythagorean Theorem

18^{2}+24^{2}=

18

2

+24

2

=

\,\,c^{2}

c

2

Plug in. c is the hypotenuse.

324+576=

\,\,c^{2}

c

2

Square the numbers.

900=

\,\,c^{2}

c

2

Add.

\sqrt{900}=

900

=

\,\,\sqrt{c^{2}}

c

2

Square root both sides.

30=

\,\,c

c

The hypotenuse.

7 0

3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

4 years ago

2 3 − 5 6 ·8<br><br> Simplify.

Helga [31]

Answer:

-1.33 and so on

Step-by-step explanation:

Take each fraction and plug it into a calculator. 2/3 is really 2 divide by 3. Same with the 5 and 6. You should get 0.67 and so on for 2/3 and 0.83 and so on for the 5/6. Subtract as shown in the problem. You should get 0.67-0.83= -0.1666 so on. Multiply by 8 to get -1.33 and so on. The "and so on" means this decimal is repeating. Hope this Helps!

5 0

3 years ago

Read 2 more answers

Joy is making hand-painted ornaments for

Nutka1998 [239]

Answer:

1 ornament per 3 hours

in 15 hours she will have 7.5 of them done

7 0

2 years ago

Read 2 more answers

Simplify<br> (4x² – 2x + 8) - (x² + 3x - 2)