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2 years ago

11

PLEASE HELP! I WILL GIVE BRAINLIEST! When a photo is reduced or enlarged its length to width ratio usually remains the same. Aur

elia wants to enlarge a 4" x 6" photo so that it has a width of 15 inches use a ratio table to determine the new lengths of the photo.

1 answer:

polet [3.4K]2 years ago

4 0

Length = 4 6 8 10
Width = 6 9 12 15

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They want me to start with one triangle and add 2 tooth picks each time but how do I do that

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Add them all around the top pointing down

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2 years ago

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For f(x) = 3x^2 + 2x - 1, identify the rule for g(x) = f(x + 1) - 6 and it's graph.

PilotLPTM [1.2K]

2x2 + x −#6 _____________

x2 − 1

∙ x

__

2 + 2x + 1

x 2 − 4

Rewrite as multiplication.

(2x − 3)(x + 2) __

(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.

(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Multiply numerators and denominators.

(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Cancel common factors to simplify.

(2x − 3)(x + 1) __ (x − 1)(x − 2)

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3 years ago

Graph the point (5, 0) on the coordinate plane.

gavmur [86]

Answer:

it just be positive 5

Step-by-step explanation:

3 0

2 years ago

A restaurant manager can spend at most $600 a day for operating costs and payroll. It costs $100 each day to operate the bank an

navik [9.2K]

Option A

The restaurant Manager can afford at most 10 employees for the day

<em><u>Solution:</u></em>

Given that restaurant manager can spend at most $600 a day for operating costs and payroll

It costs $100 each day to operate the bank and $50 dollars a day for each employee

The given inequality is:

$50x + 100\leq 600$

Where , "x" is the number of employees per day

Let us solve the inequality for "x"

$50x + 100\leq 600$

Add -100 on both sides of inequality

$50x + 100 - 100\leq 600 - 100\\\\50x\leq 500$

Divide by 50 on both sides of inequality

$\frac{50x}{50}\leq \frac{500}{50}\\\\x\leq 10$

Hence the restaurant Manager can afford at most 10 employees for the day

Thus option A is correct

6 0

3 years ago

1.A cube has side lengths of 15 inches, what is the surface area and volume of the cube? 2. A cube has side lengths of 8 inches,

omeli [17]

Answer:

Cube 1: 3375 cubed inches, 1350 inches squared.

Cube 2: 512 cubed inches, 384 inches squared.

Step-by-step explanation:

Formula for Volume of a Cube: $V=s^3\\$ (s - side length)

Formula for Surface Area of a Cube: $SA=6s^2$ (s- side length)

<h3>For Cube 1:</h3>

The side length's 15 inches.

Find the volume:

$V=15^3\\\rightarrow 15*15*15=3375\\\boxed {V=3375}$

The volume of cube one is 3375in³.

Find the surface area:

$SA=6(15)^2\\\rightarrow 15^2 = 225\\SA = 6 * 225\\\boxed {SA=1350}$

The surface area of cube 1 is 1350in².

<h3>For Cube 2:</h3>

The side length's 8 inches.

Find the volume:

$V=8^3\\\rightarrow 8*8*8= 512\\\boxed {V=512}$

The volume of cube two is 512in³.

Find the surface area:

$SA=6(8)^2\\\rightarrow 8^2=64\\SA=6*64\\\boxed {SA=384}$

The surface area of cube 2 is 384in².

<em>Brainilest Appreciated. </em>

3 0

3 years ago