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2 years ago

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PLEASE HELP! I WILL GIVE BRAINLIEST! When a photo is reduced or enlarged its length to width ratio usually remains the same. Aur

elia wants to enlarge a 4" x 6" photo so that it has a width of 15 inches use a ratio table to determine the new lengths of the photo.

1 answer:

polet [3.4K]2 years ago

4 0

Length = 4 6 8 10
Width = 6 9 12 15

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Use an inequality symbol to compare -3 +7____-10-2

Damm [24]

Answer:

-3+7 > -10-2

Step-by-step explanation:

-3+7 = +4

-10-2 = -12

∴ +4 > -12

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2 years ago

Gina is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 12 inches by 14 1/4 inc

Fittoniya [83]

Answer:

278.63 square inches

Step-by-step explanation:

Gina needs to cut two types of rectangles.

Dimensions of one rectangle is given as,

Width = 12 inches

Length = $14\frac{1}{4}$ = $\frac{57}{4}$ inches

So, the area of this rectangular paper will be

Area = width × length = $12\times \frac{57}{4}$ = 171 inches²

Dimensions of the other rectangular paper has been given as

Width = $10\frac{1}{4}$ = $\frac{41}{4}$ inches

Length = $10\frac{1}{2}$ = $\frac{21}{2}$ inches

So, the area of this rectangle will be

Area = width × length = $\frac{41}{4} \times \frac{21}{2}$ = 107.63 inches²

Thus the total area she need to cut = 171 + 107.63 = 278.63 square inches.

6 0

3 years ago

Read 2 more answers

Please I really need help on this

Ilya [14]

Answer:

40%

Step-by-step explanation:

She has sold 20 items total.

Refrigerators: 8/20 = 40%

Dishwashers: 1/20 = 5%

Dryers: 11/20 = 55%

So there is a 40% chance she will sell another refrigerator! hope this helps!!

3 0

2 years ago

Two ways to simplify 2(5ft + 3ft)

strojnjashka [21]

Either you can use distributive property or you can add up the numbers in the brackets.
Hopefully that helped! :)

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3 years ago

Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t

Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

$\frac{dy}{dx}=0$ (The slope is zero)

--To obtain vertical tangent lines, the condition is:

$\frac{dy}{dx}=\frac{1}{0}$ (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

$\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}$ = $2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0$

Solving for dy/dx:

$\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}$

Applying the first conditon (slope is zero)

$\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0$

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

$x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2$

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

$x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1$

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

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3 years ago