Answer:
The possible approximate frequencies of the guitar string are 516.82 Hz and 508.82 Hz
Step-by-step explanation:
The given period of the tuning fork, T₁ = 1.95 × 10⁻³ s
The number of beats in 6.0 s = 24 beats
Therefore, the beat frequency,
= 4 beats per second = 4 Hz
Let f₁ represent the frequency of the tuning fork, and let f₂ represent the frequency of the guitar string, we have;
f₁ = 1/T₁ = 1/(1.95 × 10⁻³) ≈ 512.82 Hz
We have;


Therefore, we get;

f₂ - 512.82 = ± 4
∴ f₂ = 512.82 ± 4
The possible frequencies of the guitar string, f₂ ≈ 516.82 Hz or f₂ ≈ 508.82 Hz
-13 is the smallest among these integers.
Answer:
slope intercept form of the equation for these points would be y=2x-7
standard form of linear equations for this equation would be: -2x+y=-7
Step-by-step explanation:
9514 1404 393
Answer:
16 and 17
Step-by-step explanation:
16² = 256
(√277)² = 277
17² = 289
The root of 277 is between 16 and 17.