Answer:
Probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.
Step-by-step explanation:
We are given that a certain car model has a mean gas mileage of 31 miles per gallon (mpg) with a standard deviation 3 mpg.
A pizza delivery company buys 43 of these cars.
<em>Let </em>
<em> = sample average mileage of the fleet </em>
<em />
The z-score probability distribution of sample average is given by;
Z = 
~ N(0,1)
where, 
= mean gas mileage = 31 miles per gallon (mpg)
= standard deviation = 3 mpg
n = sample of cars = 43
So, probability that the average mileage of the fleet is greater than 30.7 mpg is given by = P(<em> </em>> 30.7 mpg)
P(<em> </em>> 30.7 mpg) = P( > 
) = P(Z > -0.66) = P(Z < 0.66)
= 0.7454
<em>Because in z table area of P(Z > -x) is same as area of P(Z < x). Also, the above probability is calculated using z table by looking at value of x = 0.66 in the z table which have an area of 0.7454.
</em>
Therefore, probability that the average mileage of the fleet is greater than 30.7 mpg is 0.7454.
T = 2
1. Divide both sides by 2
--> t / 2
=
2. Square both sides
-->
/ 4
= m / k
3. Multiply both sides by k
--> m = k
/ 4
Answer:
Pieces remaining = 1 - (1/4 + 1/4) - (1/2 x1/5) = 1/2 - (1/2 x1/5) = 1/2 - 1/10 = 4/10
Therefore, 4/10 x 20 = 8 pieces.
Step-by-step explanation:
Sophie ate 1/4 = 5 pieces
Glenn ate 1/4 = 5 pieces
Remaining pieces = 20 - 5 - 5 = 10 pieces
On Monday, Sophie ate = 1/5 x 10 = 2 pieces
Therefore, remaining pieces = 10 - 2 pieces = 8 pieces
Sophie and Glenn consumed half of the pie the first day. This is equal to 10 pieces. The remaining pieces will be 10. If, on Monday, Sophie ate 1/5 of 10 pieces, representing 2 pieces, the number left over is 10 Minus 2, which equals 8 pieces.
Answer:
A and C
Step-by-step explanation:
Answer:
woah woah slow down man my computer wont let me take screenshots but they intersect
Step-by-step explanation:
