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lianna [129]
3 years ago
15

How to solve a quadratic equation that does not factor?

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0
Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
If the quadratic is ax²+bx+c, x=(-b+√b²-4ac)/2a.
If b² > 4ac the solutions are real. If b²-4ac is a perfect square, the solutions are real and rational; otherwise they’re real but irrational.
If b² < 4ac the solutions are complex.
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3 years ago
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5 0
2 years ago
4(0.5f−0.25)=6+f what is f<br><br><br> I am so lost when we were doing this in class
muminat
4 (0.5f - 0.25) = 6 + f
2.0f - 1.0 = 6.0 + f
1.00f = 6.0 + f
f = -5.0
hope this is right,
~ Harley Quinn~
8 0
3 years ago
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Butoxors [25]
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4 0
3 years ago
Please help fast to. ​
Eva8 [605]

Answer:

C.

Step-by-step explanation:

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3 years ago
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