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omeli [17]
3 years ago
14

The linear function that is represented by which table has the same slope as the graph? On a coordinate plane, a line goes throu

gh points (0, negative 3) and (2, 1). A 2-column table with 5 rows. Column 1 is labeled x with entries negative 25, negative 21, negative 17, negative 13, negative 9. Column 2 is labeled y with entries negative 9, negative 7, negative 5, negative 3, negative 1. A 2-column table with 5 rows. Column 1 is labeled x with entries negative 25, negative 21, negative 17, negative 13, negative 9. Column 2 is labeled y with entries 9, 7, 5, 3, 1. A 2-column table with 5 rows. Column 1 is labeled x with entries negative 9, negative 7, negative 5, negative 3, negative 1. Column 2 is labeled y with entries negative 25, negative 21, negative 17, negative 13, negative 9. A 2-column table with 5 rows. Column 1 is labeled x with entries 1, 3, 5, 7, 9. Column 2 is labeled y with entries negative 9, negative 13, negative 17, negative 21, negative 25.

Mathematics
2 answers:
lions [1.4K]3 years ago
6 0

Answer:

c

step-by-step explanation:

ok the slope of the line is 2

and so by using the formula y1+y2/x1+x2 we can get the ration of each table

the first table is  -9+-7/-25+-21

this can be simplified to  -16/-46 which is about  0.347

using this formula for each table you can find the answer .

im

too lazy to do the rest

   

svetoff [14.1K]3 years ago
4 0

Answer:

It's C

Step-by-step explanation:

I did the quiz, see Arjinoodles for a detailed explanation.

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given that a1=5 and a2=15 are the first two terms of a geometric sequence, determine the values of a3 and a10. Show the calculat
Alekssandra [29.7K]

a_3 is 45 and a_10 is 98415

Step-by-step explanation:

Given

a_1 = 5

a_2 = 15

First of all we have to calculate the common ratio of the sequence. The common ratio is the ratio between two consecutive terms of a geometric sequence.

So,

r=\frac{a_2}{a_1} = \frac{15}{5} = 3

The explicit formula for geometric sequence is:

a_n = a_1.r^{n-1}

Putting the value of r and a_1

a_n = 5.(3)^{n-1}

Putting n=3 in the explicit formula

a_3 =5.3^{3-1}\\= 5 * 3^2\\=5 * 9\\= 45

Putting n=10 for tenth term

a_{10} =5.3^{10-1}\\=5*3^9\\=5 * 19683\\=98415

Hence,

a_3 is 45 and a_10 is 98415

Keywords: Geometric sequence, Explicit formula

Learn more about geometric sequence at:

  • brainly.com/question/10978510
  • brainly.com/question/11007026

#LearnwithBrainly

7 0
3 years ago
Best tip for Maths test to figure out challenging problems​
padilas [110]
  • First solve the easier questions which can be solved in very low time.
  • Drop out the harder questions for last.
  • After completing the easier questions take your time to complete harder ones.
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3 0
3 years ago
Find the value of x in the solution to the system of equations shown.
ale4655 [162]
<span>y=4x-6
y=-4x+48
</span>4x-6= -4x+48
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8 0
4 years ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
3 years ago
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