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3 years ago

The measures of two angles of pairs of triangles are given. Which pairs of triangles are similar?

Mathematics

2 answers:

nasty-shy [4]3 years ago

8 0

Answer:

1, 2, and 5 are similar

Step-by-step explanation:

morpeh [17]3 years ago

6 0

If the triangles are similar then the angles in both are equal. Let's look at each set individually:

(1) Triangle 1: 25°, 35°
Triangle 2: 25°, 120°
Now it may be hard to tell if the triangles are similar at the moment so we must calculate the third angle in each triangle (The angles in a triangle add up to 180°, therefor the missing angle = 180 - (given angle 1 + given angle 2)
Triangle 1: 180 - (25 + 35) = 120°
Triangle 2: 180 - (25 + 120) = 35°

Now writing out the set of angles again we have:
Triangle 1: 25°, 35°, 120°
Triangle 2: 25°, 120°, 35°

So in fact Triangle 1 and 2 are similar.

Now we can repeat this process for (2) - (5):

(2) Triangle 1: 100°, 60°, 20°
Triangle 2: 100°, 20°, 60°
This pair is also similar

(3) Triangle 1: 90°, 45°, 45°
Triangle 2: 45°, 40°, 95°
This pair is not similar

(4) Triangle 1: 37°, 63°, 80°
Triangle 2: 63°, 107°, 10°
This pair is not similar

(5) Triangle 1: 90°, 20°, 70°
Triangle 2: 20°, 90°, 70°
This pair is similar

Therefor pairs (1), (2) and (5) are similar

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Lee watches TV for 2 hours per day. During that time, the TV consumes 250 watts per hour. Electricity costs (10 cents)/(1 kilowa

vladimir1956 [14]

Answer:

$1.5

Step-by-step explanation:

Lets us first calculate energy consumed by TV in 30 days.

Energy consumed by TV in one hour : 250 watts.

TV operated 2 hours a day

so energy consumer by TV in a day = 250 * 2 watts = 500 watts hour

Energy consumed by TV in 30 day = energy consumer by TV in a day * 30

= 500*30 watts = 15,000 watt-hour

Convert total energy consumed in kilo watt hour

we know that one kilowatt hour = 1000 watt-hour

Thus, 15,000 watt-hour = 15,000/1000 kilowatt-hour = 15 kilowatt-hour

________________________________

cost of electricity = 10 cents per kilowatt-hour

cost of electricity for 15 kilowatt-hour = 15* cost of electricity for one kilowatt-hour( which is 10 cents)

=>15*10 = 150 cents

As $1 = 100 cents

hence 150 cents = $150/100 = $1.5 .

Thus, it cost $1.5 to to operate for a month of 30 days.

6 0

3 years ago

If somebody can give me an explanation on how to do this i would appreciate it!

Natali5045456 [20]

The answer is 4+(9x1/10)+(5x1/1000)

Can i have a brainiest

4 0

3 years ago

@bobross plz help I have another question

enot [183]

Answer:

Average velocity is 32 miles/hr.

Step-by-step explanation:

Given that a particle moves on a line away from its initial position so that after t hours it is $s=6t^2+2t$ miles from its initial position.

We have to find the average velocity of the particle over the interval [1, 4].

As, average velocity is the change is position over the change in time.

$s(4)=6(4)^2+2(4)=104$

$s(1)=6(1)^2+2(1)=8$

∴ $\text{Average Velocity=}\frac{s(4)-s(1)}{4-1}$

= $\frac{104-8}{3}=\frac{96}{3}=32miles/hr$

Hence, average velocity is 32 miles/hr.

6 0

3 years ago

Read 2 more answers

1. -7-(-2) *

Morgarella [4.7K]

1. -7-(-2)
= -7+2= -5

2. 5-(-3)
= 5+3=8

3. -6-4
= -6+(-4)= -10

4. -3-(-3)
= -3+3= 0

8 0

3 years ago

A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2

dlinn [17]

Answer:

The surface area of the second cylinder is equal to $9.33\ m^{2}$

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

$z^{2}=\frac{x}{y}$

Step 1

Find the scale factor

$z=\frac{2}{6}=\frac{1}{3}$

Step 2

Find the surface area of the second cylinder

we have

$z=\frac{1}{3}$

$y=84\ m^{2}$

substitute and solve for x

$(\frac{1}{3})^{2}=\frac{x}{84}$

$x=\frac{1}{9}*84=9.33\ m^{2}$

5 0

3 years ago