Answer:
Step-by-step explanation:
y = -x + 1......same as y = -1x + 1.....in y = mx + b form, ur slope is in the m position....so the slope of this line is -1.
a parallel line will have the same slope.
(-1,3)...x = -1 and y = 3
slope(m) = -1
y = mx + b.....we have x,y, and m....now we need to find y int (b)
3 = -1(-1) + b
3 = 1 + b
3 - 1 = b
2 = b
so ur parallel equation is : y = -1x + 2...or just y = -x + 2
Answer:
Step-by-step explanation:
Use Pythagorean to find the missing side x of the triangle.
<u>It is a hypotenuse with other sides 18 in and half of 15 in:</u>
<u>The perimeter is:</u>
It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
Answer:
y = 1/2x + 1
Step-by-step explanation:
Slope: 1/2
Point: (2,2)
y-intercept: 2 - (1/2)(2) = 2 - 1 = 1
