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Vsevolod [243]
2 years ago
14

Show 2-(-3) on a number line.

Mathematics
1 answer:
9966 [12]2 years ago
3 0
Just put a closed circle above 5 on the # line.
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Can someone help simplify?: -8x^3y2(2x^4y^4)
Kisachek [45]

So the rule with multiplying exponents of the same base is to add the exponents together. Applying this rule here would look like this:

-8x^3y^2*2x^4y^4=(-8*2)x^{3+4}y^{2+4}=-16x^7y^6

In short, your simplified expression is going to be -16x^7y^6.

3 0
3 years ago
For the following equation, what would you do first? -8n+4(1-5n)=-6n-14
Mkey [24]

Answer:

1-5n

Step-by-step explanation:

you would do 1-5n because its in brackets, the order of opperation is

Brakcets

Order (Power ofs)

Division and Mulitplication

then do addition and subtraction

when doing division and multiplication and subtraction and addition go left to right to find what part goes 1st.

Hope this helped!

4 0
2 years ago
Solve <br> - 5 3/4 - 3 1/2 = ???
ollegr [7]

Answer:

-9 1/4

Step-by-step explanation:

- 5 3/4 - 3 1/2

= -23/4 - 7/2

= -23/4 - 14/4

= -37/4

= - 9 1/4

4 0
3 years ago
Read 2 more answers
Compare these data sets. The equation of the trend line is listed below each data set.
Luda [366]

Answer:

b and e

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
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