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Anvisha [2.4K]
3 years ago
5

A basketball coach is ordering jerseys for members of the basketball team and can choose between small, medium, and large jersey

s. The cost of a small jersey is x dollars. The cost of a medium jersey is 1 dollar more than the small jersey, and the cost of a large jersey is 2 dollars more than the medium jersey. The coach orders 5 medium jerseys and 7 large jerseys for a total cost of $146. The equation below can be used to find the cost, in dollars, of one small jersey. 5(x + 1) + 7(x + 3) = 146 Enter the cost, in dollars, of one small jersey.

Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0
Feel free to ask if you still don't understand :)

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Answer:

Addition is...

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then the sum will be 3.14 + 5 = 8.14

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Please help and I will give you brainliest 5 stars and a thank you on answer and profile just please help
defon

Answer:

#1 D. 360

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Step-by-step explanation:

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Each person in random samples of 207 male and 253 female working adults living in a certain town in Canada was asked how long, i
Sergeu [11.5K]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females (P-value=0.155).

Step-by-step explanation:

The data is:

Males n1=207 M1=31.6 s1=24.0

Females n2=253 M2=29.3 s2=24.3

This is a hypothesis test for the difference between populations means.

The claim is that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

Then, the null and alternative hypothesis are:

H_0: \mu_m-\mu_f=0\\\\H_a:\mu_m-\mu_f> 0

The significance level is 0.05.

The sample 1 (males), of size n1=207 has a mean of 31.6 and a standard deviation of 24.

The sample 2 (females), of size n2=253 has a mean of 29.3 and a standard deviation of 24.3.

The difference between sample means is Md=2.3.

M_d=M_m-M_f=31.6-29.3=2.3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{24^2}{207}+\dfrac{24.3^2}{253}}\\\\\\s_{M_d}=\sqrt{2.783+2.334}=\sqrt{5.117}=2.262

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_m-\mu_f)}{s_{M_d}}=\dfrac{2.3-0}{2.262}=\dfrac{2.3}{2.262}=1.017

The degrees of freedom for this test are:

df=n_1+n_2-1=207+253-2=458

This test is a right-tailed test, with 458 degrees of freedom and t=1.017, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.017)=0.155

As the P-value (0.155) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean daily conmute time for males is significantly bigger than the mean daily conmute time for females.

7 0
3 years ago
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