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laila [671]
4 years ago
13

Which problem could be solved by evaluating the expression 9 × (-2)?

Mathematics
1 answer:
stiks02 [169]4 years ago
3 0

Answer:

intergers

Step-by-step explanation:

+*-=-

so 9*(-2)=-18

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A certain quadratic function has the factors
olganol [36]

Answer:

D

Step-by-step explanation:

If those two functions are the factors of a quadratic, then each of them can be equated to 0 to find the roots. Sometimes the roots are called the zeros.

2x - 5 = 0                       Add 5 to both sides

2x - 5 + 5 = 0 + 5           Combine

2x = 5                             Divide both sides by 2

2x/2 = 5/2

x = 5/2

You don't really have to find the other factor's 0 point. There is only 1 option that makes x = 5/2. On a test, it is important to take short cuts and save time.  I'll find the other root anyway because this is not a test.

3x + 4 = 0                           Subtract 4 from both sides

3x + 4-4 = 0 - 4                  Combine

3x = - 4                               Divide both sides by 3

3x/3 = - 4/3

x = - 4/3

7 0
2 years ago
If jamie completed 5 chores, about how much money did she earn?
QveST [7]

Answer:

5(chore payment)

Step-by-step explanation:

since we dont know how much money the chore is worth it would be 5 times the money

4 0
2 years ago
The telephone company purchased 192 yards of wire for $2,304 in January. They
Aleks [24]

Answer:

Step-by-step explanation:

400yd($2304/192yd)=$4800

6 0
3 years ago
Read 2 more answers
What is the value of x in the figure below?
Leviafan [203]
180-115=65
65+70=135
180-135=45

SO C.45
8 0
3 years ago
What expression is equivalent to 3(x+4)^2
eimsori [14]

Hello there,

Well we are given with 3(x + 4)² and we need to simplify this expression...

  1. write out the expression: 3(x + 4)(x + 4)
  2. then we distribute the parentese: 3(x² +4x +4x +16)
  3. combine like terms: 3(x² + 8x + 16)
  4. distribute the 3 in the parentese: 3x² + 24x + 48

So another way to express this would be 3x² + 24x + 48.

Hope I helped,

Amna

8 0
3 years ago
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