Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
Well it depends on what Ice Cream flavors are being Debated on.
Step-by-step explanation:
Factor x^2 + x - 6
(x - 2)(x + 3) = 0
Solve for x
Ask yourself; When will (x - 2)(x + 3) equal zero?
When x - 2 = 0 or x + 3 = 0
Then solve for each of the two equations above
<em>x = 2, -3</em>
<u>Answer: C. 2, -3</u>
Answer: 128/15 min or 8.5 min
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a. f(a) =5a+12
we have 1. a=6
Therefore, where ever we find a we'll substitute in 6
f(6) =5(6) +12
6f=30+12
6f=42
so therefore 1. a=6 will match c on the right
2. a=2
f(2) =5(2) +12
2f = 10+12
2f = 22
therefore 2. a=2 will match a on the right
3. a=4
f(4) =5(4) +12
4f=20+12
4f=32
therefore 3. a=4 will match d on the right
4. a=5
f(5) =5(5) +12
5f=25+12
5f=37
therefore 4. a=5 will match b on the right
