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3 years ago

Find the y-intercept of the line: -2x -3y = 18

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

5 0

Answer:

y = -2/3x -6

Step-by-step explanation:

-2x -3y = 18

+2x +2x

-3y = 2x + 18

-3y/-3 = 2x/-3 + 18/-3

y = -2/3x -6

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3 years ago

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Answer: The answer is $3\dfrac{4}{7}.$

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$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

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3 years ago