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kodGreya [7K]
4 years ago
12

If f(x) = 2x and g(x) = sqrt x,what is the domain of (fog)(x)?

Mathematics
1 answer:
Norma-Jean [14]4 years ago
7 0

Answer:

All Real x larger or equal zero

or in inequality form: x\geq 0

or in interval notation: [0,\infty)

Step-by-step explanation:

If f(x)=2x and g(x)=\sqrt{x}, then using the definition for the composition of functions (fo\,g)(x)=f(g(x)), we get:

(fo\,g)(x)=f(g(x)) \\(fo\,g)(x)=f(\sqrt{x} )\\(fo\,g)(x)=2\,\sqrt{x}

Base on this final expression, we understand that the Domain (numbers that can be used as input of the function and produce a real number as result) of this new function is limited to those x-values larger than or equal to zero. Negative numbers inside the square root will not produce a real number.

Therefore, the Domain is restricted to All Real numbers larger than or equal to o (zero).

This statement can also be given in inequality form as x\geq 0

or in interval notation: [0,\infty)

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biancas employer matches 25% of her 401(k) contributions u to $1000 biancas salary is $50000 and last year she contributed $6000
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Five more than seven time a number is ninerty-six.what is the number?
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B.HELPPPP MEEEE PLSSSS AND THANK YOUU
Gemiola [76]

Answer:

A. (3, 8) and 2\sqrt{2}

B. (2, 4) and 2\sqrt{10}

Step-by-step explanation:

Midpoint formula: (\frac{x1+x2}{2} ,\frac{y1+y2}{2})

Distance formula: \sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }

A. plug in the points in the formulas

(4, 7) and (2, 9)

Midpoint:

(\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)

Length:

\sqrt{(2-4)^2+(9-7)^2}=\sqrt{4+4} =\sqrt{8} =2\sqrt{2}

B.

(5, 5) and (-1, 3)

Midpoint:

(\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)

Length:

\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}

Can you consider marking my answers as brainliest lol it would mean a lot. Hope this helped.

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