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inn [45]
2 years ago
9

4(−15−3p)−4(−p+5) Expand the expression and combine like terms

Mathematics
2 answers:
Allushta [10]2 years ago
8 0
Ok so when you distribute you get -60-12p+4p-20 then you will do -60+-20 which is -80 then you do -12p+4p which you get -8p then overall its -8p-80
sergij07 [2.7K]2 years ago
4 0
4(−15−3p)−4(−p+5)
-60-12p -4(-p+5)
-60-12p +4p-20
-80-12p+4p
-80-8p

Rearrange into standard form
-8p-80

Final answer: -8p-80
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Which function has an inverse that is also a function
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In order for a function to have an inverse that is also a function there are 2 main requirements:

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Hope this answer helps you..

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3 years ago
A​ quality-control manager randomly selects 80 bottles of oil that were filled on january 14 to assess the calibration of the fi
Simora [160]

Is this all the information provided or are you missing something?

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3 years ago
If U = {x: X € N, 1 < × < 15)
Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

verifies

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3 years ago
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LuckyWell [14K]
3=y and 2=x



Pretty sure that’s right
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