We know that
a1=1
a2=3
a3=9
a2/a1=3/1----> 3
a3/a2=9/3----> 3
<span>common ration r is equal to 3
number of terms n is 12
The </span><span>Sum of geometric series is given by the formula
</span>Sum=a1*[1-r<span>^n]/[1-r]
</span>Sum=1*[1-3^12]/[1-3]-----> Sum=[1-3^12]/[1-3]----> [3^12-1]/[3-1]
<span>Sum=531440/2-----> 265720
the answer is
265720
</span>
Answer:
42.5 if rounding 43 for B
Step-by-step explanation:
P is the variable so put 100 under it
Then on the first empty fraction put 17/40
Cross multiply
You will get 40p=17x100
So then you multiply 17 by 100
1700
divided both sides by 40
Get the variable alone
Divide 1700 by 40
get 42.5
If your teacher is as annoying as mine round to 43
Answer:
\angle ACB=40^{\circ}, \angle ABC=63^{\circ}
Step-by-step explanation:
Finding x:
We know that 
, because it's a straight line. So, 
.
We know that the sum of the angles of any triangle will be 
.
So, we have that 
.
Combining like terms on the left gives 
.
Subtracting 
from both sides gives 
.
Dividing both sides by 
gives 
.
Finding missing angle measures:
.
.
So, 
and 
and we're done!
Note: 
. Coincidence? If not, try and prove it!
Answer: x = -1 and y = 9
The two equations are:
-9x + 2y = 23
-4x -y = -3
Now find for x in the first equation...
-9x + 2y = 23
-9x = 23 - 2y
x = (23 - 2y)/-9
Now place this value of x in the second equation and find for y...
-4{(23-2y)/-9} - y = -3
-92 + 8y + 9y = -3 * -9
17y = 27 + 92
y = 119/17
y = 7
Now place the value of y in the first equation," -9x + 2y = 23 " and find x
-9x + 2*7 = 23
-9x + 14 = 23
-9x = 23-14
x = 9/-9
x = -1
There you go! Hope it helps
<h2>૮꒰ ˶• ༝ •˶꒱ა
</h2><h2>./づᡕᠵ᠊ᡃ࡚ࠢ࠘ ⸝່ࠡࠣ᠊߯᠆ࠣ࠘ᡁࠣ࠘᠊᠊°
</h2>
i shoot u >:(
<h2>
</h2><h2>૮꒰ ˶> ༝ <˶꒱ა
</h2><h2>./づᡕᠵ᠊ᡃ࡚ࠢ࠘ ⸝່ࠡࠣ᠊߯᠆ࠣ࠘ᡁࠣ࠘᠊᠊°.~♡︎
</h2>
with love tho-
Answer:
A. −7 < x < 6.
Step-by-step explanation:
x: −8 < x − 1 < 5
--->
−7 < x < 6
