Answer:
first four terms are 2, 7, 12, 17
Step-by-step explanation:
use this formula:
=
+ (n - 1)· d
where 'n' equals the position in the sequence the term is in and 'd' is the common difference
if
= 2 and d = 5 are given, plug those into formula
= 2
= 2 + (2 - 1)·5 = 2+5 = 7
= 2 + (3 - 1)·5 = 2+2(5) = 12
= 2+(4 - 1)·5 = 2+3(5) = 17
Hella easy, the answer would be C(-2,3) D(-2,5)
Answer:
a = 2/27
b = 13/27
Step-by-step explanation:
The given polynomial is presented as follows;
f(x) = a·x³ + b·x² + x + 2/3
Given that x + 3 is a factor, we have;
f(-3) = 0 = a·(-3)³ + b·(-3)² - 3 +2/3 = 0
-27·a + 9·b - 3 + 2/3 = 0
-27·a + 9·b = 7/3........(1)
Also we have
(a·x³ + b·x² + x + 2/3) ÷ (x + 2) the remainder = 5
Therefore;
a·(-2)³ + b·(-2)² + (-2) + 2/3 = 5
-8·a + 4·b - 2 + 2/3 = 5
-8·a + 4·b = 2 - 2/3 = 4/3........(2)
Multiplying equation (1) by 4/9 and subtracting it from equation (2), we have;
-8·a + 4·b - 4/9×(-27·a + 9·b) = 4/3 - 4/9 × 7/3
-8·a + 12·a = 8/27
4·a = 8/27
a = 2/27 ≈ 0.0741
imputing the a value in equation (1) gives;
-27×2/27 + 9·b = 7/3
-2 + 9·b = 7/3
9·b = 7/3 + 2 = 13/3
b = 13/27 ≈ 0.481.
Answer:
Round off to closest value.
Step-by-step explanation:
In order to remove the requirement for change, every time the client buys a product for $0.20 the random number that lies between 0 and 1 would be produced also the same would be rounded to the closest value i.e. 0 or 1. In the case when 0 arise so the customer would not have to pay any amount but if 1 arise so the customer have to pay $1. So this type of method would remove the requirement for a minor change