How to work out 189,232÷8

Mathematics

1 answer:

Tcecarenko [31]3 years ago

8 0

The answer would be 23,654.

Use long divison to figure it out or a calcualtor.

You might be interested in

Please answer this correctly

Andreyy89

Answer: 1-20=2 and 60-80=4

Step-by-step explanation:

the first is 2 number of building

and the third one is 4 number of buldings

Hope this helps :)

7 0

3 years ago

If a is an odd integer and b is an even integer, which of the following makes an odd integer?

Serga [27]

9514 1404 393

Answer:

D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

A) 3(0) = 0 . . . even

B) 1 +3 = 4 . . . even

C) 2(1+0) = 2 . . . even

D) 1 +2(0) = 1 . . . odd

_____

Additional comment

These rules apply to even/odd:

odd × odd = odd
odd × even = even
even × even = even
odd + odd = even
odd + even = odd
even + even = even

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

7 0

2 years ago

20 POINTS!!!

notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$