PLEASE PLEASE PLEASE HELP! WILL BE GIVING OUT BRAINLIEST AND LOTS OF POINTS!!!!!!!

1 answer:

4 0

No,The room is not a square shaped.This is because.Perimeter of the square shape would be length of any sides×4 as all sides will be the same in a square.Therefore, if the room ia a square, the 4 sides of room floor will be equal too.It is not a square shaped room beacause it sides are not equal for floor.We can determine by finding the sides;
diagonal is 18.75 so by using pythagoras theorem
diagonal^2 =l^2 + b^2
b^2=18.75^2 + 17^2
b =25.31 inches which is not the same as the length 17 inches.Therefore,the room is not a square

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Solve each quadratic equation by completing the square. Give exact answers--no decimals.

Sholpan [36]

Answer:

$x_1 = -2 + 2i\\\\x_2 = -2 -2i$

Step-by-step explanation:

In this problem we have the equation of the following quadratic equation and we want to solve it using the method of square completion:

$7x ^ 2 + 28x +56 = 0$

The steps are shown below:

For any equation of the form: $ax ^ 2 + bx + c = 0$

1. If the coefficient a is different from 1, then take a as a common factor.

In this case $a = 7$ . Then:

$7(x ^ 2 + 4x) = -56$

2. Take the coefficient b that accompanies the variable x. In this case the coefficient is 4. Then, divide by 2 and the result squared it.

We have:

$\frac{4}{2} = 2\\\\(\frac{4}{2})^2 = 4$

3. Add the term obtained in the previous step on both sides of equality, remember to multiply by the common factor $a = 7$ :

$7(x ^ 2 + 4x + 4) = -56 + 7(4)$

4. Factor the resulting expression, and you will get:

$7(x + 2) ^ 2 = -28$

Now solve the equation:

Note that the term $7(x + 2) ^ 2$ is always $> 0$ therefore it can not be equal to -28.

The equation has no solution in real numbers.

In the same way we can find the complex roots:

$7(x+2)^2 = -28\\\\(x+2)^2 = -\frac{28}{7}\\\\x+2 = \sqrt{-\frac{28}{7}}\\\\x = -2 + \sqrt{-4}\\\\x = -2 + 2\sqrt{-1}\\\\x_1 = -2 + 2i\\\\x_2 = -2 -2i$