In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get A=180-(E+93)
So, by alternate segment theorem, DCE= A.
thats all i can say.
Answer:
A. 
B. Perimeter = 190.6 yd
Step-by-step explanation:
A. Distance between P(10, 50) and R(80, 10):





(nearest tenth)
B. Distance around the park = Perimeter = PR + PQ + QR
PR = 80.6 yd
PQ = |50 - 10| = 40 yd
QR = |80 - 10| = 70 yd
Perimeter = 80.6 + 40 + 70
Perimeter = 190.6 yd
Answer:
1st one
Step-by-step explanation:
Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:

Introducing the constant of proportionality

If 150 pounds is required for a distance of 10 inches from the object

Therefore, the relationship between p and d is:

When d=3 Inches

The pressure applied when the distance is 3 inches is 500 pounds.
Answer:
c=3
Step-by-step explanation:
4c+12-2c=5c-3 1. combine like terms
2c+12=5c-3 2. -5c on both sides
-3c+12=3 3. -12 on both sides
-3c=-9 4. /-3 on both sides
c=3