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Kazeer [188]
2 years ago
9

My question is in the picture pls help

Mathematics
2 answers:
Viktor [21]2 years ago
8 0

Answer:

probally 80 or 90

Step-by-step explanation:

Anna007 [38]2 years ago
3 0

Answer:

109°

Step-by-step explanation:

subtract 180 from 71 and you will get 109°

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Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.
VladimirAG [237]
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
7 0
2 years ago
A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).
juin [17]

Answer:

A. PR = 80.6 yd

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}

PR = \sqrt{(70)^2 + (-40)^2}

PR = \sqrt{4,900 + 1,600}

PR = \sqrt{6,500}

PR = 80.6 yd (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

7 0
2 years ago
What’s the answer to this question. <br> Simple correct answers
Sophie [7]

Answer:

1st one

Step-by-step explanation:

5 0
3 years ago
The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc
AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

p \propto \dfrac{1}{d}

Introducing the constant of proportionality

p = \dfrac{k}{d}

If 150 pounds is required for a distance of 10 inches from the object

  • p=150 pounds
  • d=10 inches

150 = \dfrac{k}{10}\\\\k=1500

Therefore, the relationship between p and d is:

p = \dfrac{1500}{d}

When d=3 Inches

p = \dfrac{1500}{3}\\\implies p=500$ pounds

The pressure applied when the distance is 3 inches is 500 pounds.

4 0
3 years ago
Using the table below, complete and explain the process used for each step in solving the equation. 4c+ 12-2c = 5c - 3​
Oduvanchick [21]

Answer:

c=3

Step-by-step explanation:

4c+12-2c=5c-3  1. combine like terms

2c+12=5c-3    2. -5c on both sides

-3c+12=3      3. -12 on both sides

-3c=-9       4. /-3 on both sides

c=3

6 0
2 years ago
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