Hello there, Lithommie
You see accroding to newtons gravitational law an object that weighs more on earth wieghs less in space due to the lack of strenthness of gravity.
If my answer helped you understand more clearly i would glady apriciate brainliest thank you and have a great day!
Answer:
10(3)^x
Step-by-step explanation:
The function contains the points (2,90) and (4,810). Use the general form y=abx to write two equations:
90=ab^2 and 810=ab^4
Solve each equation for a:
a=90/b^2 and a=810/b^4
Since a=a, set the other sides of the equations equal and solve for b.
90/b2=810/b4
Cross multiply, then divide and simplify as follows:
90b^4=810b^2
b^4/b^2=810/90
b^2=90
b^3
Now, use the value of b and the point (2,90) to find the value of a.
90=a(3^2)
a=10
So, substitute answers in original equation for a final answer of f(x)=10(3)^x.
Answer and Step-by-step explanation:
Considering the table attached.
(a) over 9.5 kg;
μ = 8
σ = 0.9
z = 9.5 - 8/0.9 ≈ 1.67
P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475
(b) at most 8.6 kg;
z = 8.6-8/0.9 ≈ 0.67
P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486
(c) between 7.3 and 9.1 kg.
z₁ = 7.3-8/0.9 ≈ -0.78
z₂ = 9.1 - 8/0.9 ≈ 1.22
P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711
From the graph, the domain of the function will be {x| x = −2,1}. Then the correct option is D.
<h3>What is an asymptote?</h3>
An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.
From the graph, the domain of the function will be
The function is not defined for x = 2 and x = -1.
Then the domain will be
{x| x = −2,1}
Then the correct option is D.
More about the asymptote link is given below.
brainly.com/question/17767511
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