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4 years ago

Help someone please ASAP

Mathematics

1 answer:

Klio2033 [76]4 years ago

7 0

3 x 4 = 12

3 + 4 = 12

The two integers a and b are : 3 and 4

-4 x 1 = -4

-4 + 1 = -3

The two integers a and b are : -4 and 1

-3 x -3 = 9

-3 + -3 = -6

The two integers a and b are : -3 and -3

There you go! I really hope this helped, if there's anything just let me know! :)

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Please help me with #7

Dominik [7]

Step-by-step answer:

This is a regular heptagon, means it has 7 <em>congruent</em> sides and 7 <em>congruent </em>vertex angles.

To work with polygons, there is a very important piece of information that you must know to solve the majority of related problems.

This is:

sum of exterior angles of polygons = 360 degrees.

If you don't remember the 360 degrees, think of the sum of exterior angles of an equilateral triangle, which is 3*(180-60)=3*120=360! It works!

For a regular heptagon, c = 360/7=51.43 degrees approx.

This means that each vertex angle measures

vertex angle = 180-c

So since 2d+the vertex angle = 360, we have

2d+(180-c)=360

solve for d:

2d=360-(180-c)=180+c

d=(180+c)/2=90+c/2=115.71 degrees. (approx.)

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3 years ago

Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

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Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

$v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}$

$v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}$

$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

$\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

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