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Mice21 [21]
3 years ago
6

Math help mee plzzzzzz THERE IS A ATTACHMENT SO WAIT AT LEAST 30 SECONDS PLZZZZME

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
I hope this helps you


25$-14$=11$ a month

6 month 6.11$=66$
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Hello can anyone help me ? here the question
lesantik [10]

Answer:

A. 1/5k - 2/3j and -2/3j +1/5k

Step-by-step explanation:

A. 1/5k - 2/3j and -2/3j +1/5k

B. 1/5k - 2/3j and -1/5k +2/3j

There is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

Not equivalent

C. 1/5k - 2/3j and 1/5j - 2/3k

There is a change in the variables

1/5k changed to 1/5j

-2/3j changed to -2/3k

D. 1/5k - 2/3j and 2/3j - 1/5k

The is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

The only equivalent expression is

A. 1/5k - 2/3j and -2/3j +1/5k

3 0
3 years ago
Which graph represents the solution set of the system of inequalities? {x+y<12 y≥x−4
RSB [31]

Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

5 0
2 years ago
Read 2 more answers
Help please im lost and not good in math
Damm [24]
Answers: a = 49
b = 10
c = 105
8 0
3 years ago
Read 2 more answers
What is the original price of ATV set if you paid 1035 for it after a 10% discount
oksano4ka [1.4K]

Answer:

$1150

Step-by-step explanation:

To be honest, this is the type of question I straight up solve in my head. Sorry for the no explanation.

5 0
2 years ago
Which expression shows that the quotient
Harrizon [31]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

We further simplify this expression,

\frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

= \frac{2}{(3x-1)}\times \frac{6x-1}{6}

= \frac{6x-1}{3(3x-1)}

= \frac{6x-1}{(9x-3)}

Therefore, \frac{6x-1}{(9x-3)} will be the quotient of the given expression.

x\neq \frac{1}{3} and x\neq \frac{1}{6} for which the given expression is not defined.

Option (2) will be the answer.

6 0
3 years ago
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