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Nadusha1986 [10]
3 years ago
12

How do you solve this ? what do you do with the exponets ?

Mathematics
2 answers:
Vikki [24]3 years ago
8 0
\bf \left( 6-x \right)^{\frac{4}{7}}=x^{\frac{4}{7}}\impliedby 
\begin{array}{llll}
\textit{since the exponents are the same}\\
\textit{their bases must also be the same}
\end{array}
\\\\\\
6-x=x\implies 6=2x\implies \cfrac{6}{2}=x\implies 3=x
antiseptic1488 [7]3 years ago
6 0
4/7 is the answer. 

I cant reall explain becuase it will take forever xD
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Here is a probability scale
xxMikexx [17]

Answer:

a) e

b) c

c) a

Step-by-step explanation: Look at the number line. 0 shows that it has no probability while C is at 1/2 showing that it could be half-half. Then you can see one under E which means it is bound to happen.

5 0
3 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0
3 years ago
How many times greater is the value of 83 than the value 0.083?
Inessa [10]
1000 times greater (1K)
5 0
3 years ago
Louise begins factoring the polynomial, which has four terms.
ad-work [718]

Louise wants to factorize completely the given polynomial 4x^{3}+12x^{2}+5x+15

Grouping first, second terms together and third, fourth terms together

= 4x^{3}+12x^{2}+5x+15

Taking 4x^{2} common from first and second terms of the given expression and taking 5 common from the third and fourth terms.

==4x^{2}(x+3)+5(x+3)

Taking (x+3) common from the given expression,

==(4x^{2}+5)(x+3) is the completely factored form.

5 0
3 years ago
Fifteen people were asked how many days it had been since they had eaten more than 50 grams of carbohydrates in a single day. Th
sukhopar [10]
It's C
Because I know it
4 0
3 years ago
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