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3 years ago

How do you solve this ? what do you do with the exponets ?

Mathematics

2 answers:

Vikki [24]3 years ago

8 0

$\bf \left( 6-x \right)^{\frac{4}{7}}=x^{\frac{4}{7}}\impliedby 
\begin{array}{llll}
\textit{since the exponents are the same}\\
\textit{their bases must also be the same}
\end{array}
\\\\\\
6-x=x\implies 6=2x\implies \cfrac{6}{2}=x\implies 3=x$

antiseptic1488 [7]3 years ago

6 0

4/7 is the answer.

I cant reall explain becuase it will take forever xD

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MM13 (Minute Math 13) 7th Grade Math

taurus [48]

Answer: um, sorry but you said it have 10 question right but Where all the question if you put a picture here then I don’t see it, I Ward love to help you, Really I do but I don’t see the question..... I’m not here to got your point but I’m Just telling you all this and I’m sorry again.

Step-by-step explanation:

6 0

3 years ago

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago

Solve Z-8/4=-1 1. Z= -12 2. Z= 28 3. Z= 4 4. Z= -36

Gnesinka [82]

Answer:

Step-by-step explanation:

8 0

3 years ago

Hellllp pleaseeeeeeeeeeeeeeeeeee

sukhopar [10]

Step-by-step explanation:

750000 / 1500 = 500

with a 100% mark up cost it will cost p1000

6 0

3 years ago

Find the inverse of the given function.

ad-work [718]

Y = $\frac{2x+42}{19}$

You can get this by switching the x and f(x) in the equation and then solve for f(x)

f(x) = 19/2x - 21 ---> now switch them
x = 19/2f(x) - 21 ---> now add 21 to both sides
x + 21 = 19/2f(x) ---> now multiply by 2/19 on both sides
(2x + 42)/19 = f(x) ---> ANSWER

6 0

3 years ago