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3 years ago

5 1/3% is equal in fraction to 4/75 true or false

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

True, as 5 1/3% = 16/3 * 1/100 = 16/300. 16/300 simplifies to 4/75 as the gcf(16,300) = 4.

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Which of these are symptoms of schizophrenia?. A. expressing emotions less intensely B.compulsively repeating an action C.wantin

k0ka [10]

Answer:A,D,F

Step-by-step explanation:

I just passed this one

5 0

3 years ago

Anyone can do this please if you can do all of it of you can I'm really bad at math

Vilka [71]

Im Gonna Do 14 And 15.

14:
3/4 (9/12) + 1/3 (4/12) = 13/12
4/5 (16/20) - 1/4 (5/20) = 11/20

15:
-15 < -6
-31 < -19
-5 < 20
-21 < -15
0 < 22
-57 < -26
-71 < -10
3 < 21
-124 < 30
-43 < 18

Hope This Helps!

7 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

8 0

2 years ago

Samuel bought a jacket for $16 in January. The cost of the jacket increased to $24 in September. What percent of the original pr

garri49 [273]

Write a proportion first, change over original, like this:
8 x
16 100
(I got 8 because the difference between 24 and 16 is 8 and I got 100 because percents are out of 100.)
Cross multiply 8 by 100 and you get 800.
Divide 800 by 16 and you get 50.
It changed by 50%

6 0

3 years ago

Read 2 more answers

Write an equation perpendicular to the line 6x+12y=24 and passing through (4,0)

noname [10]

Y = 2x - 8 is perpendicular to 6x+12y=24 and passes through (4,0)

6 0

3 years ago