Answer:
2/3
Step-by-step explanation:
Given that a six sided die with sides labelled with numbers 1,2,3,4,5 and 6 is rolled once.
Since die is said to be equally likely for each number, die is unbiased
P(1) = P(2)=...=P(6) = 1/6
For a number greater than 2, we must not include 2 and hence numbers can be 3 or 4 or 5 or 6
Probability of rolling a number >2 = Probability of rolling 3 or 4 or 5 or 6
= P(3)+P(4)+P(5)+P(6)
= 1/6+1/6+1/6+1/6
=4/6
=2/3
Required probability = 2/3
