Question

Work out the area of triangle ABC. B. 25 cm A 32 cm D 2 cm

Answer 1

Answer:

Step-by-step explanation:

ΔADB is a right angled triangle. So, use Pythagorean theorem.

Altitude² = hypotenuse² - base²

               = (2√5)² - (3√2)²

              = 2²* (√5)² - 3²*(√2)² = 4*5 - 9*2 = 20 - 18 = 2

Altitude = √2

Base of ΔABC = 3√2 + √2 = 4√2 cm

Area = $\dfrac{1}{2}bh$

         $= \dfrac{1}{2}*4\sqrt{2}*\sqrt{2}\\\\\\=\dfrac{1}{2}*4*\sqrt{2*2}\\\\\\=\dfrac{1}{2}*4*2\\\\= 4 cm^{2}$