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AVprozaik [17]
3 years ago
7

If you wish to edit a data source in a document, you can make modifications when you select the data sources or _____.

Computers and Technology
2 answers:
lisov135 [29]3 years ago
8 0

Answer

when you preview your letters

Explanation:

inna [77]3 years ago
4 0

The answer is when you preview your letters

I just took the quiz and got it wrong.

Hope this helps someone!

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1. Which of the following is not a question that should be asked when planning a Windows Server 2019 installation?
sashaice [31]

Answer:

1 B 2 C and B 3 True

Explanation:

3 0
3 years ago
In order to paint a wall that has a number of windows, we want to know its area. Each window has a size of 2 ft by 3 ft. Write a
Oksana_A [137]

Answer:

The program in Java will be:

import java.util.Scanner;

public class Paint

{

   public static void main(String[] args)

   {

       final int COVERAGE = 350;  //paint covers 350 sq ft/gal

       final int DOOR = 20;

   final int WINDOW = 15;    

   //declare integers length, width, and height;

   int length, width, height, doors, windows;

   //declare double totalSqFt;

   double totalSqFt;

       //declare double paintNeeded;

   double paintNeeded;

     //declare and initialize Scanner object

   Scanner scan = new Scanner (System.in);

   //Prompt for and read in the length of the room

   // finish this -- length =  

   System.out.print("Enter the length of the room: ");

   length = scan.nextInt();

   //Prompt for and read in the width of the room

       System.out.print("Enter width: ");

   width = scan.nextInt();

       //Prompt for and read in the height of the room

   System.out.print("Enter height: ");

   height = scan.nextInt();

       //Prompt for and enter the number of doors    

   System.out.println("Enter the number of doors: ");

   doors = scan.nextInt();

   //Prompt for and enter the number of windows

   System.out.println("Enter the number of windows: ");

   windows = scan.nextInt();

   //Compute the total square feet to be painted--think

      //about the dimensions of each wall

       totalSqFt = 2 * width * height + 2 * length * height - DOOR*doors - WINDOW*windows;

       //Compute the amount of paint needed

       paintNeeded = totalSqFt / COVERAGE;

       //Print the length, width, and height of the room and the

       //number of gallons of paint needed.

   System.out.println("Length= " + length + "\nWidth= " + width +  "\nHeight= " + height + "\nNumber of doors: " + doors + "\nNumber of windows: " + windows + "\nGallons of Paint Needed= " + paintNeeded);

   

   }

}

5 0
4 years ago
Read 2 more answers
write a while loop that reads integers from input and calculates integer finalnum as follows: if the input is divisible by 5, ad
ira [324]

The while loop for the program that reads integers from input and calculates integer is illustrated thus:

#include <iostream>

using namespace std;

int main()

{

//declaring the variables

int userInput;

int outputVal;

outputVal = -19;

//take user input

cin >> userInput;

//take user input until negative input is given

while(userInput > 0)

{

 //if the input is divisible by 5, subtract the

 //input divided by 5 from outputVal

 if(userInput%5==0)

     outputVal -= userInput/5;  

 //if the input is not divisible by 5, add the

 //input multiplied by 5 from outputVal

  else

     outputVal += userInput*5;

   cin >> userInput; // take input

}

//print the output value

  cout << "Output value is " << outputVal << endl;

return 0;

<h3>What is a while loop?</h3>

A while loop is a control flow statement in most computer programming languages that allows code to be performed repeatedly based on a supplied Boolean condition. The while loop is similar to a looping if statement.

A "While" Loop is used to iterate over a certain block of code until a condition is met. If we wish to ask a user for a number between 1 and 10, we don't know how many times the user may enter a larger number, so we keep asking "while the number is not between 1 and 10."

Learn more about program on:

brainly.com/question/22654163

#SPJ1

7 0
1 year ago
There are well-known classes of problems that are intractably difficult for computers, and other classes that are provably undec
Wittaler [7]
No. It is not impossible to understand and make this algorithm a success. It may only take a longer duration to reach success but it does not that it is impossible. Problems may become more difficult to understand and debug but there is enough time, duration, resources and support, the algorithm can be developed.
4 0
3 years ago
Please tell fast plzzzzzz.​
lana [24]

Answer:

True

Explanation:

4 0
3 years ago
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