To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
x = [-5 ± √(25 - (132) ) ] / ( -22 )
x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.
Answer:
q = 2
Step-by-step explanation:
0.5-0.125q=(q-1)/4
At first, we have to multiply both the sides by 4.
4 × (0.5 - 0.125q) = q - 1
or, 2 - 0.5q = q - 1
now, we change the side by taking constant into the right side and the number into the left side.
2 + 1 = q + 0.5q
or, 3 = q (1 + 0.5)
or, 3 = 1.5 q
or, 1.5 q = 3
or, 
= (3 ÷ 1.5) [Dividing both the sides by 1.5]
or, q = 2
Therefore, q = 2
It would be an isosceles triangle. Since there are two sides of the triangle that are congruent, it would be isosceles.
Isosceles has two congruent sides, scalene has none, and equilateral has three.
(A good tip to do is this: count the number of syllables in each word. Then take away two. That's how many sides that triangle has.)
Ex: i-so-sce-les has four syllables. Take away two, you get two. Therefore, an isosceles triangle has two congruent sides.
Hope that helps!
Answer:
idk
Step-by-step explanation:
idk
