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DanielleElmas [232]

3 years ago

13

A multiplication table. In the row labeled 3, the numbers 9, 12, 15, and 18 are highlighted. Consider the highlighted products.

The common factor is _____.

1 answer:

Basile [38]3 years ago

3 0

3, 3x3=9, 3x4=12, 3x5=15, 3x6=18

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Use the rule for y= -6x +8 to find the output if the input is x=20

lisov135 [29]

Answer:

The output of the function y = -6x + 8 when the input is x = 20 is -112.

Step-by-step explanation:

y = -6x + 8

Input the value x = 20.

y = -6(20) + 8

Multiply -6 and 20.

y = -120 + 8

Add -120 and 8.

y = -112.

8 0

3 years ago

in Hanley's school, 0.723 of the students participated in an event. if there are 1000 students in Hanley School, how many partic

Ugo [173]

Answer:

723 students participated in the event

Explanations:

The total number of students in Hanley's school = 1000

0.723 of the students participated in an event

Number of students that participated in the event = 0.723 x 1000

Number of students that participated in the event = 723

4 0

1 year ago

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

faust18 [17]

Answer:

Sample Response: To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.

6 0

3 years ago

A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat

iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

$n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\$

The implicit derivative with respect to the time would be

$\frac{dn}{dt} = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt} + \frac{4pr^3}{v}\frac{dr}{dt} )$

If we multiply everything by dt we get

$dn = \frac{\pi}{8} ( \frac{r^4}{v} dp + \frac{4pr^3}{v} dr})$

Remember that the error is given by $\frac{dn}{n}$ therefore doing some algebra we get that

$\frac{dn}{n} = 4 \frac{dr}{r} + \frac{dp}{p}$

Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that

$\frac{dn}{n} = 0.1714$

Which means that the maximum error for viscosity is 17.14%.

5 0

3 years ago

Tony misplaced 7 77 stamps from his collection. He knows that each stamp of his is worth $ 0 . 1 5 $0.15dollar sign, 0, point, 1

denis23 [38]

I take it that only 7 stamps are misplaced and that we are asked for the total value of the stamps including those which have been misplaced.
If each is worth $0.15 then, the total worth of 7 stamps is $1.05. Then, we add this value to the value of his remaining stamps, $5.55, the answer would be $6.60.

7 0

3 years ago