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3 years ago

I need to figure this out cause idk.

Mathematics

1 answer:

jeka57 [31]3 years ago

6 0

Since she flipped the coin 20 times and got 4 heads and 6 tails, you put it as a fraction. So, it's 4/16 if you simplify 4 over 16 you get 1/4. You get this by dividing by 4 both numbers.

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Line p has an x-intercept of 5 and a y-intercept of 3. Find the slope of line p

Vitek1552 [10]

Answer:

-3/5

Step-by-step explanation:

you can use the formula $\frac{y_2-y_1}{x_2-x_1}$ to find the slope of a line when given two points.

we are given both the x and y intercepts, and we can use those in the formula.

the x intercept is (5,0) and the y intercept is (0,3)

i will treat (5,0) as my x1 and y1, and (0,3) as my x2 and y2

$\frac{3-0}{0-5}$ = -3/5

the slope is -3/5

6 0

3 years ago

How many more brooms must each earn in order to have enough credit to get a month off with pay?

tester [92]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

An automatic filling machine is used to fill bottles with liquid detergent. A random sample of 18 bottles results in a sample st

Nookie1986 [14]

Answer:

$\frac{(17)(0.038)^2}{32.64} \leq \sigma^2 \leq \frac{(17)(0.038)^2}{6.66}$

$0.0008 \leq \sigma^2 \leq 0.0037$

Step-by-step explanation:

Data given and notation

s=0.038 represent the sample standard deviation

$\bar x$ represent the sample mean

n=18 the sample size

Confidence=97.5% or 0.975

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

Since the Confidence is 0.975 or 97.5%, the value of $\alpha=0.025$ and $\alpha/2 =0.0125$ , and we can use excel, a calculator or a table to find the critical values.