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lidiya [134]
3 years ago
7

The tortoise and the hare are in a road race to defend the honor of their breed. the tortoise crawls the entire 1000. m distance

at a speed of 0.2000 m/s while the rabbit runs the first 200.0 m at 2.000 m/s the rabbit then stops to take a nap for 1.300 hr and awakens to finish the last 800.0 m with an average speed of 3.000 m/s. who wins the race and by how much time?
Mathematics
1 answer:
jolli1 [7]3 years ago
5 0
<span>The tortoise crawls the whole 1000 m at 0.2 m/s, therefore, you must divide the distance by the rate of travel to find the time it took to complete the race. This gives us a time of 5,000 seconds to crawl the thousand meters. The hare runs the first 200 meters at 2 m/s, meaning that takes 100 seconds. The last 800 meters divided by the speed of 3 m/s gives us a time of 266 seconds. These two numbers must be added to the hare's rest time, converted from 1.3 hours into seconds by multiplying that number by 60 (for minutes in an hour) then 60 again (for seconds in a minute). 1.3 hours is equal to 4680 seconds. Therefore, the whole race took the hare 5,046 seconds, making it slightly slower than the hare, who finished in 5,000 seconds flat.</span>
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Solve for y: 8x - 3y = 17
vladimir2022 [97]

Answer:

x = 2.125 + 0.375y

Step-by-step explanation:

Simplifying

8x + -3y = 17

Solving

8x + -3y = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3y' to each side of the equation.

8x + -3y + 3y = 17 + 3y

Combine like terms: -3y + 3y = 0

8x + 0 = 17 + 3y

8x = 17 + 3y

Divide each side by '8'.

x = 2.125 + 0.375y

Simplifying

x = 2.125 + 0.375y

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3 years ago
The national mean SAT score in math is 550. Suppose a high school principal claims that the mean SAT score in math at his school
creativ13 [48]

Answer:

Option B) Reject the null hypothesis. There is sufficient evidence to suggest that the students' mean SAT score is greater than 550. The principal was right.

Test statistics = 2.036

P- value = 2.07% .

Step-by-step explanation:

We are given that the population mean, \mu = 550  {National mean SAT score}

We have to test the principal claim that the mean SAT score in math at his school is better than the national mean score or not.

Let              <em>Null Hypothesis, </em>H_0<em> : </em>\mu<em> = 550</em>

<em>           Alternate Hypothesis, </em>H_1<em> : </em>\mu<em> > 550 </em>

The test statistics we will use here is;

             \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } follows N(0,1)

     where, Xbar = 574    and \sigma(Population standard deviation) = 100

                  n = sample of students = 72

 Test Statistics =  \frac{574 - 550}{\frac{100}{\sqrt{72} } } = 2.036

<em>Now at 5% level of significance the z table gives the critical value of 1.6449 and our test statistics is more than this as 2.036 > 1.6449 so we have sufficient evidence to reject null hypothesis and conclude that there is sufficient evidence to suggest that the students' mean SAT score is greater than 550. The principal was right. </em>

P - value = P(Z > 2.04) = 0.0207 or 2.07%

Here also our P- value is less than the level of significance of 5% ,we will reject null hypothesis.

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4 years ago
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