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ASHA 777 [7]
3 years ago
10

Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train

A heading towards station A, and train B heading towards station B. Train A reaches station A after 3 h. Train B reaches station B after 214 h. Station A and Station B are 420 mi apart. What is the rate of the trains?
Mathematics
2 answers:
Art [367]3 years ago
6 0
So you want to make it: total distance (d) = rate (r) × total time (t), solving for r: r = d / t
r = (420mi) / (3h+214h), r = 420mi / 217h
r = 1.935mi/h = 1.94mi/h
serious [3.7K]3 years ago
6 0
It's 80  ((((((((((((((((((:
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02-3+30-8+p+p
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Alina [70]

Answer:

C

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ludmilkaskok [199]
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7 0
3 years ago
How to find this answer using sine or cosine law?
SashulF [63]

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From the Given Triangle we Can Notice that :

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5 0
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How to do this and how to find the numbers for it?
hodyreva [135]
So I have the formula for the reflection over the x-axis is from (x,y) to (x,-y), and the reflection for the y-axis is (-x,y). Next, I have the original for A(2,-2), B(2,-6), and (9,-6) which is reflection over x-axis which is A(2,2), B(2,6), and C(9,6). Then, I have A(-2,-2), B(-2,-6), and C(-9,-6) for the reflection over the y-axis. Hope it help!
5 0
3 years ago
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