All categories

2 years ago

Help me please? :( (;´༎ຶД༎ຶ`)(;´༎ຶД༎ຶ`)(;´༎ຶД༎ຶ`)

Mathematics

1 answer:

Gnesinka [82]2 years ago

5 0

Answer:

a) 22:53

b)213 min

Step-by-step explanation:

c) 10 17 + 4 = 14 17

she has 2 minutes to spare

You might be interested in

Which of the following statements is true?. . A.A tangent is never a secant.. B.A secant is always a chord.. C.A chord is always

skelet666 [1.2K]

The <em>correct answer</em> is:

A) A tangent is never a secant.

Explanation:

A tangent is a line that touches a circle in exactly one point. A secant is a line that touches a circle in two different points.

Since a tangent only touches once and a secant touches twice, there is no way a tangent can be a secant.

3 0

2 years ago

What is the surface area in square inches of the prism

Lerok [7]

Answer: the answer is 25

Step-by-step explanation:

7 0

2 years ago

A birdwatcher on a cliff saw a eagle 70 feet above him. Earlier, he had spotted the eagle 30 feet above him. Which integer repre

loris [4]

Answer:

40° or feet

Step-by-step explanation:

4 0

2 years ago

Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio

Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

$SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2} } }{N} }$

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

$X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\$

3. Caclulate Standard deviation:

$SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2} } }{5} }$

$SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251$

7 0

2 years ago

How do you find DE, Round to nearest 10th

Sergeu [11.5K]

Answer: $DE\approx6.0$

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

$cos\alpha=\frac{adjacent}{hypotenuse}$

From the figure you can identify that:

$\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE$

Then, you can substitute values:

$cos(53\°)=\frac{DE}{10}$

The next step is to solve for DE in order to find its value. This is:

$10*cos(53\°)=DE\\\\DE=6.01$

Finally, rounding the result to the nearest tenth, you get that this is:

$DE\approx6.0$

7 0

2 years ago