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3 years ago

What is the relationship between 12 and -12

Mathematics

1 answer:

Lelu [443]3 years ago

5 0

Answer:

opposite

Step-by-step explanation:

12 and -12 are opposite.

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I would much appreciate the explanation for number 20 cuz ion’ get it

cestrela7 [59]

Answer:

Which is number 20?

Step-by-step explanation:

Which is number 20?

6 0

3 years ago

Read 2 more answers

Which of the following is equal to the function below? (7/4)^11

solmaris [256]

Answer:

Therefore the correct option is A. 7^11/4^11

$(\dfrac{7}{4})^{11}=\dfrac{7^{11}}{4^{11}}$

Step-by-step explanation:

Given:

$(\dfrac{7}{4})^{11}$

Solution:

We know the Identity For Law of Indices

$(\dfrac{x}{y})^{a}=\dfrac{x^{a}}{y^{a}}$

So here we have,

x = 7

y = 4

a = 11 , then

$(\dfrac{7}{4})^{11}=\dfrac{7^{11}}{4^{11}}$

Therefore the correct option is A. 7^11/4^11

$(\dfrac{7}{4})^{11}=\dfrac{7^{11}}{4^{11}}$

7 0

4 years ago

Jason owns two square plot of land that have the same dimensions. He subdivides one into 10 equal parcels and the other into 11

Ymorist [56]

No, they do not yield the same amount of land.

If you divide a number by 10, you get a larger result than if you divide it by 11. So let's say the area of the two squares is 110:

110/10 = 11 for each parcel

110/11 = 10 for each parcel

4 0

3 years ago

I’m gonna be asking a lot of these so if your good at these then watch out for more! :)

inna [77]

Answer:

Step-by-step explanation:

Please give me brainliest :)

8 0

3 years ago

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In the formula A(t) = A0ekt, A(t) is the amount of radioactive material remaining from an initial amount A0 at a given time t an

Alenkasestr [34]

Answer: 693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

$A(t) =A_0e^{kt}$

k = rate constant

t = time taken for decomposition = 1

$A_0$ = Initial amount of the reactant

$A_t$ = amount of the reactant left = $A_0-\frac{0.1}{100}\times A_0=0.999A_0$

$0.999A_0=A_0e^{k\times 1}$

$0.999=e^k$

$k=-0.001year^{-1}$

for half life : $t=t_\frac{1}{2}$

$A_t=\frac{1}{2}A_o$

Putting in the values , we get

$\frac{1}{2}A_0=A_0e^{-0.001\times t_\frac{1}{2}$

$t_\frac{1}{2}=693 years$

Thus half life of this isotope, to the nearest year is 693.

8 0

4 years ago