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dsp73
3 years ago
11

What is the relationship between 12 and -12

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

opposite

Step-by-step explanation:

12 and -12 are opposite.

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I would much appreciate the explanation for number 20 cuz ion’ get it
cestrela7 [59]

Answer:

Which is number 20?

Step-by-step explanation:

Which is number 20?

6 0
3 years ago
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Which of the following is equal to the function below? (7/4)^11
solmaris [256]

Answer:

Therefore the correct option is A. 7^11/4^11

(\dfrac{7}{4})^{11}=\dfrac{7^{11}}{4^{11}}

Step-by-step explanation:

Given:

(\dfrac{7}{4})^{11}

Solution:

We know the Identity For Law of Indices

(\dfrac{x}{y})^{a}=\dfrac{x^{a}}{y^{a}}

So here we have,

x = 7

y = 4

a = 11 , then

(\dfrac{7}{4})^{11}=\dfrac{7^{11}}{4^{11}}

Therefore the correct option is A. 7^11/4^11

(\dfrac{7}{4})^{11}=\dfrac{7^{11}}{4^{11}}

7 0
4 years ago
Jason owns two square plot of land that have the same dimensions. He subdivides one into 10 equal parcels and the other into 11
Ymorist [56]
No, they do not yield the same amount of land.

If you divide a number by 10, you get a larger result than if you divide it by 11. So let's say the area of the two squares is 110:

110/10 = 11 for each parcel

110/11 = 10 for each parcel
4 0
3 years ago
I’m gonna be asking a lot of these so if your good at these then watch out for more! :)
inna [77]

Answer:

55

Step-by-step explanation:

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8 0
3 years ago
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In the formula A(t) = A0ekt, A(t) is the amount of radioactive material remaining from an initial amount A0 at a given time t an
Alenkasestr [34]

Answer:  693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

A(t) =A_0e^{kt}

k = rate constant

t = time taken for decomposition = 1

A_0 = Initial amount of the reactant

A_t = amount of the reactant left =A_0-\frac{0.1}{100}\times A_0=0.999A_0

0.999A_0=A_0e^{k\times 1}

0.999=e^k

k=-0.001year^{-1}

for half life : t=t_\frac{1}{2}

A_t=\frac{1}{2}A_o

Putting in the values , we get

\frac{1}{2}A_0=A_0e^{-0.001\times t_\frac{1}{2}

t_\frac{1}{2}=693 years

Thus half life of this isotope, to the nearest year is 693.

8 0
4 years ago
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