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mezya [45]
3 years ago
10

I need help ASAP please

Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

65 degrees

Step-by-step explanation:

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Question 11<br><br> (-10) + (10) = ??<br> A)20<br> B)-20<br> C)-0<br> D)0
Nastasia [14]

Answer:

0

Step-by-step explanation:

-10 + 10

-10 and 10 are additive inverses, so when we add them, it is equal to zero

-10 + 10 = 0

6 0
3 years ago
Jeremiah ran 5.6 miles every day for<br> 2 weeks. How many miles did he run<br> in all?
chubhunter [2.5K]

Answer:

78.4 miles

Step-by-step explanation:

Since there are 14 days in two weeks, you multiply 5.6 miles times 14 days to get 78.4 miles in total since 5.6 is how much he ran every DAY

3 0
2 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
2. Ms. Groves has trays of paints for students in her
olga55 [171]

Answer:

Each tray has 5 colours and one of the colour on the tray is purple. Hence 1/5 of the colours on the tray is purple and thus 1/5 of the colours on the 20 trays is purple. The fraction of colours on the trays will not change. If written out logically, 20 purples out of 100 colours in total on the trays will also given the fraction 1/5.

4 0
3 years ago
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

Hence, option A is true.

3 0
2 years ago
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