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mezya [45]
3 years ago
10

I need help ASAP please

Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

65 degrees

Step-by-step explanation:

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There are 366 days in a leap year and 24 hours in a day. How many hours are in a leap year?
Vanyuwa [196]

Answer: 8784

Step-by-step explanation: Just multiply 366 and 24

6 0
3 years ago
In order to store paint, a factory has purchased a cylindrical tank that is 6 feet across and 9 feet deep. What is the maximum n
SOVA2 [1]

Answer:

254 cubic feet.

Step-by-step explanation:

It is given that the a cylindrical tank is 6 feet across and 9 feet deep. It means

Diameter of cylinder = 6 feet

Radius of the cylinder = 6/2 = 3 feet

Height of the cylinder = 9 feet

The volume of a cylinder is

V=\pi r^2h

where, r is radius and h is height of the cylinder.

Substitute r=3 and h=9 in the above formula.

V=\pi (3)^2(9)

V=81\pi

V=254.46900

We need to find the maximum number of cubic feet. So approx the value to a whole number.

V\approx 254

Therefore, the maximum number of cubic feet of paint the tank will hold is 254 cubic feet.

8 0
3 years ago
10. Jack needs new brakes for his car. He cannot afford to spend more than $500 to fix his car. If the parts
mestny [16]

Answer:

6 hours

Step-by-step explanation:

500=165+55h

-165

335=55h

-------------

55

h=6.090909...

h=6 hours max

8 0
3 years ago
Read 2 more answers
Write the square roots of 49 i in ascending order of the angle.
Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}}  =  \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°))  and  7·(cos(45°) + i·sin(45°))

8 0
3 years ago
Please help me with this question! Thank you :)
madreJ [45]

Answer:

y=x-3

Step-by-step explanation:

Graph y=x-5 and the point (1,-2). You want your slope to be the same for the lines to be parallel. The slope in the given equation is 1/1. Type into a graphing calculator y=x- and pick a number greater than negative five since the point (1,-2) is above the given line. Guess and checking reveals -3 to be the correct answer. Therefore, your answer is y=x-3.

5 0
3 years ago
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