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ankoles [38]
3 years ago
9

I need to find Y=Mx+b. I found M but i forgot how to find B. Help

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
4 0
B is the y-intercept. in this example, b=50
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IgorC [24]

Answer:

D

Step-by-step explanation:

A: You wear a glove on your hand

B:Same answer as A

C:A wool sock is worn on your foot but it's not made of leather

D:Is made of leather and can be worn on your foot

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4 years ago
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A rhombus has a base of 8 centimeters and a height of 4.2 centimeters. What is its area? Do not round your answer.
KiRa [710]

Answer:

33.6\ cm^{2}

Step-by-step explanation:

Given that

The Base of a rhombus = 8 centimetres

Height of a rhombus = 4.2 centimetres

Based on the above information, the area of a rhombus is

Area\ of\ rhombus = Base \times height

= 8 \times 4.2

= 33.6\ cm^{2}

By multiplying the base of a rhombus with the height of a rhombus we can get the area of the rhombus and the same is applied & shown in the computation part i.e to be shown above

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3 years ago
Please Help! :) <br> Solve for X. The polygons in each pair are similar.
Diano4ka-milaya [45]

Answer:

x=2.65

Step-by-step explanation:

First, we need to figure out how much the length of the sides is changing between the equations. In this case it is changing by a factor of 2.5. Now we need to work backwards. First use this equation:

4x-5*2.5=14

This is because whatever the length of the side with x is, will be 14/2.5. So divide both sides by 2.5:

4x-5=5.6

Next, add 5 to both sides:

4x=10.6

Then divide both sides by 4:

x=2.65

8 0
3 years ago
Use the fact that the length of an arc intercepted by an angle is proportional to the radius to find the area of the sector give
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\bf \textit{area of a sector of a circle}\\\\&#10;A=\cfrac{\theta  r^2}{2}~~&#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad radians\\&#10;------\\&#10;r=3\\&#10;\theta =\frac{\pi }{4}&#10;\end{cases}\implies A=\cfrac{\frac{\pi }{4}\cdot 3^2}{2}\implies A=\cfrac{\frac{9\pi }{4}}{2}&#10;\\\\\\&#10;A=\cfrac{9\pi }{4}\cdot \cfrac{1}{2}\implies A=\cfrac{9\pi }{8}
6 0
3 years ago
PLEASE HELP ME I WILL CHOOSE BRAINLIEST!!!!
kakasveta [241]

Answer:

Exact height = 8*sqrt(3) mm

Approximate height = 13.856 mm

=============================================================

Explanation:

If you do a vertical cross section of the cylinder, then the 3D shape will flatten into a rectangle as shown in the diagram below.

After flattening the picture, I've added the points A through F

  • point A is the center of the sphere and cylinder
  • points B through E are the corner points where the cylinder touches the sphere
  • point F is at the same horizontal level as point A, and it's on the edge of the cylinder.

Those point labels will help solve the problem. We're told that the radius of the sphere is 8 mm. So that means segment AD = 8 mm.

Also, we know that FA = 4 mm because this is the radius of the cylinder.

Focus on triangle AFD. We need to find the height x (aka segment FD) of this triangle so we can then double it later to find the height of the cylinder. This in turn will determine the height of the bead.

------------------------------

As the hint suggests, we'll use the pythagorean theorem

a^2 + b^2 = c^2

b = sqrt(c^2 - a^2)

x = sqrt(8^2 - 4^2)

x = sqrt(48)

x = sqrt(16*3)

x = sqrt(16)*sqrt(3)

x = 4*sqrt(3)

This is the distance from D to F

The distance from D to E is twice that value, so DE = 2*(FD) = 2*4*sqrt(3) = 8*sqrt(3) is the exact height of the bead (since it's the exact height of the cylinder).

Side note: 8*sqrt(3) = 13.856 approximately.

8 0
3 years ago
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