What is the volume of the pyramid in cubic inches?

A social psychologist predicted that ratings of an individual’s social desirability would be influenced by their physical attrac

marshall27 [118]

Answer:

It is stated in the query that the more attractive the individual, the higher their rank of desirability.

Step-by-step explanation:

This means that we should conclude that the alternative explanation of "higher degree of desire contributes to higher levels of social attractiveness"

In the event of a null hypothesis, we will believe that the degree of attractiveness has no impact on the score of cultural desirability.

(1) Null hypothesis:- The level of attraction does not have an impact on the rating of social desirability.

(2) Alternate hypothesis:- The level of attraction has a positive effect on the ranking of social desirability.

(3) The error of Type I is characterized as the rejection of the true null hypothesis. Therefore, in this case, the type I mistake would be that "the level of attraction has a positive effect on the rating of social desirability while the level of attraction does not have an impact on the rating of social desirability."

(4) The error of type II is characterized as the failure to reject the false null hypothesis. Thus, in this situation, the Type II error would be that "the level of attraction has no impact on the rating of social desirability while the real level of attraction has a positive effect on the rating of social desirability."

(5) We know that the likelihood of having a Form I error is equal to the degree of significance (in percent terms). The significance level, in this case, is 0.05, so the likelihood of making a form I error is 0.05 * 100=5 percent.

Therefore, there is a 5 percent risk of making a Type I mistake.

3 0

3 years ago

A cruise ship maintains a speed of 10 knots (nautical miles per hour) sailing from San Juan to Barbados, a distance of 600 na

Viefleur [7K]

Answer:

a) θ=151.84°, b) t=53.73hr

Step-by-step explanation:

a)

Ok, so the very first thing we need to do when solving this problem is to draw a diagram of what the situation looks like. (See attached picture). This will help us visualize the problem better and determine what to do in order to solve it.

Notice that the ship will take a triangular path, so we can analyze it as if we were talking about a triangle. So the very first thing we need to do is find the length of side b.

We know the ship is traveling at 10knots=10 mi/hr, so we can use the following ratio to find the distance:

$V=\frac{distance}{time}$

when solving for the distance we get that:

distance=Velocity*time

since the ship will travel for 7 hours in that direction, we get that the distance it travels is:

b=10mi/hr*7hr=70mi

Once we found that distance, we can calculate the distance for side c of the triangle by using the law of cosines

$c^{2}=a^{2}+b^{2}-2ab cos \gamma$

which can be solved for c, so we get:

$c=\sqrt{a^{2}+b^{2}-2ab cos \gamma}$

since we know all those values, we can directly plug them in, so we get:

$c=\sqrt{(600mi)^{2}+(70mi)^{2}-2(600mi)(70mi) cos (25^{0})}$

which yields:

c=537.37mi

Once we know the length of c, we can use the law of sines to find angle α.

Like this:

$\frac{sin \alpha}{600}=\frac{sin 25^{o}}{537.37}$

which we can solve for α:

$sin \alpha = 600 \frac{sin 25^{o}}{537.37}$

so

$\alpha=sin^{-1}(600\frac{sin 25^{o}}{537.37})$

so we get the angle to be:

α=28.16°

now, since we are interested in finding the angle it has to turn from its origional course, we can now subtract that angle from 180° to get.

θ=180°-28.16°=151.84°

b) in order to find the time it takes to reach Barbados after the final turn is made we just need to use the velocity ratio again, but this time solve for t:

$V=\frac{c}{t}$