Answer and Step-by-step explanation:
The area formula for a Circle is:
A =
Diameter is equal to the radius times 2.
<u>So, divide the diameter to get the radius.</u>
6 divided by 2 equals 3.
<u>Now, plug it into the formula.</u>
A =
Plug this into your calculator by multiplying 9 by pi.
<u>We get the answer to be 28.3 when rounded to the nearest tenth.</u>
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<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Hi, the answer is "You pay $11 for a movie ticket and some amount at the concession stand for a total of $28". We know this because the key words "total" before $28 dollars - 'total' stands for an equal sign in equations.
The unknown, or x, is the "some amount at the concession stand". This is an unknown value, but we do know it is added to $11 dollars for the movie ticket (which is a known value.)
Therefore, we have 11 (the movie ticket) plus (key word: and) some amount (meaning x) = (key word: total) 28
Answer:
10 times less
Step-by-step explanation:
In the number 356, 740, the 4 is in the tenths place.
In 763,450, the 4 is in the hundredths place.
100/10 = 10
1. Length is 14 cm
2. Length is 20.4 cm
3. Not completely sure about 3
(Sorry hope this helps)
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.