Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Since I can’t see the figure I would have to assume that if they are the same shape and size then, yes they’re congruent.
1/3 x (3^-2 x 3^5)
1/3 x (1/3^2 x 243)
1/3 x (1/9 x 243)
1/3 x 27
9
Answer:
Step-by-step explanation:
1.458
The 5 is in the hundredths place
