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IceJOKER [234]
3 years ago
8

How many solutions does the equation 9x + 27 = 27 have?

Mathematics
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

Step-by-step explanation:

Move all terms that don't contain  

x

to the right side and solve.

x

=

0

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J. Reexamine the sequence 20, 14, 8, 2, ... from the problem
DENIUS [597]

Answer:

The n th of the given sequence is t_{n} = 26-6 n

Step-by-step explanation:

<u>Step 1</u> :-

Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.

given first term is 20 and difference isd = second term- first term = 14-20=-6

now the nth term of given sequence is

by using formula t_{n}=a+(n-1)d

t_{n}= 20+(n-1)(-6)

t_{n}= 20-6 n+6

final answer:-

t_{n} = 26-6 n

<u>verification</u>:-

t_{n} = 26-6 n

put n=1 we get first term is 20

put n=2 we get second term is 14

put n=3 we get third term is 8

put n=4 we get fourth term is 2

so the n th term of sequence is

t_{n} = 26-6 n

3 0
3 years ago
Does anyone know the answer to both of these questions????
atroni [7]

Answer:

c d

Step-by-step explanation:

3 0
3 years ago
Is number 4 correct?
Strike441 [17]

Answer:

sure

Step-by-step explanation:

6 0
3 years ago
Write each expression below in radical form and compute the value without using a calculator.
gregori [183]

Assuming that an exponentiation sign is missing, all you need to know is that rational exponents work like this:

a^{\frac{b}{c}}=\sqrt[c]{a^b}

So, you have

25^{\frac{5}{2}}=\sqrt{25^5}=\sqrt{(5^2)^5}=5^5

And similarly,

81^{\frac{7}{4}}=\sqrt[4]{25^7}=\sqrt[4]{(3^4)^7}=3^7

5 0
3 years ago
What is the x-coordinate of the point that divides the
dimaraw [331]

There's a lot of information missing here, and the given list of choices is basically incomprehensible.

Suppose J (a, b) and K (c, d) are two points in the plane. We can trace out the line segment JK joining these points with the function

r(t) = (1 - t) (a, b) + t (c, d)

where 0 ≤ t ≤ 1.

Let P be the point that divides JK into line segments JP and PK having a length ratio of 2:5. Then JP is the point 2/7 of the way along JK, so that the coordinates of P are

P = r(2/7) = 5/7 (a, b) + 2/7 (c, d) = ((5a + 2c)/7, (5b + 2d)/7)

and in particular the x-coordinate of P is (5a + 2c)/7.

6 0
2 years ago
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