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Sonbull [250]
3 years ago
5

Solve x + x + 2 + 2x = -2.

Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

-1

Step-by-step explanation:

x+x+2x=-2-2

4x=-4

x=-1

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F(x)= x^2– 3x + 9<br> g(x) = 3x^3+ 2x^2– 4x – 9<br> Find (f - g)(x).
denis-greek [22]

Answer:

\large \boxed{\sf \ \ -3x^3-x^2+x+18 \ \ }

Step-by-step explanation:

Hello, please consider the following.

(f-g)(x)=f(x)-g(x)=x^2-3x+9-(3x^3+2x^2-4x-9)\\\\=x^2-3x+9-3x^3-2x^2+4x+9\\\\=\boxed{-3x^3-x^2+x+18}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
If P is the incenter of triangle JKL, find the measure of JKP.
ladessa [460]

Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

2x = 10

x = 5

m∠KJN = (7x - 6)

            = 7(5) - 6

            = 35 - 6

            = 29°

In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = \frac{1}{2}(\angle JKN)

            = \frac{1}{2}(61)

            = 30.5°

6 0
3 years ago
Figure ABCD is similar to figure MNKL. Write a proportion that contains BC and KL.
joja [24]
B/C = K/L because they are similar
7 0
3 years ago
Round 12.5478 to the nearest hundredth's
sp2606 [1]

Answer:

I'm pretty sure it's 12.55

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
➥ The base of a parallelogram is thrice its height. If the area is 897 sq.cm. Find the base and height of the parallelogram.
IgorC [24]

Answer:

The height of parallelogram is 51.87 cm

Step-by-step explanation:

Let The height of a parallelogram = a cm

Then

The base of a parallelogram = 3a cm

So by the given condition

3a×a = 897

3a^2 = 897

a^2 = 897/3

a^2 = 299

a = 17.29

So the height of parallelogram = 3×17.29= 51.87 cm

6 0
3 years ago
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