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monitta
3 years ago
10

Miguel is making a snack mix. The recipe calls for six parts of spicy tortilla chips to three parts of corn chips. Miguel would

like to make 45 cups of snack mix. How many cups of spicy tortilla chips and corn chips does Miguel need?
PLEASE HELP!! AND EXPLAIN IF YOU CAN ❤️❤️❤️❤️❤️❤️
Mathematics
2 answers:
barxatty [35]3 years ago
4 0

Answer:

15 cups of corn chips,

30 cups of tortila chips.

Step-by-step explanation:

Since we know that Miguel needs the spicy tortila chips and corn chips in 6:3 or 2:1 ratio. We can assume that Miguel needs 2x cups of spicy tortilla chips and x cups of corn chips. Now we can set an equation as:

2x+x=45

3x=45

\frac{3x}{3}=\frac{45}{3}

x=15

Therefore, Miguel needs 15 cups of corn chips.

2x=2\times 15

2x=30

Therefore, Miguel needs 30 cups of tortila chips.

Harlamova29_29 [7]3 years ago
3 0
Equation:
6x + 3x = 45

To find X:
6x = 45
45/6 = 7.5
x = 7.5

To find other X:
3x = 45
45/3 = 15
x = 15

Final answer:

7.5 cups tortilla chips

15 cups corn chips
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Differentiate between a fixed and movable pulley.<br>​
Tamiku [17]

Answer:

Step-by-step explanation:

A fixed pulley consists of a wheel fixed to a shaft and is used in conjunction with a belt to transfer energy to another fixed pulley. A movable pulley consists of a shell, a movable wheel and a rope. Movable pulleys are also know as block and tackle.

8 0
3 years ago
Mary’s mother invested in an internet stock the price went up and down over the next few months: +32, -10 +13 -25 at the end of
babunello [35]

Answer:

higher

Step-by-step explanation:

add all of these numbers, if the sum is positive it is higher, if the sum is negative it is lower

32-10+13-25=10, this is positive so it is higher

8 0
3 years ago
A man has 1 coins in his pocket, all of which are dimes and quarters. Aif the total value of his change is $2.75, how many dimes
VLD [36.1K]

Using a system of equations, it is found that there are 5 dimes and 9 quarters in his pocket.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of dimes in his pocket.
  • Variable y: number of quarters in his pocket.

He has a total of 14 coins, hence:

x + y = 14 -> y = 14 - x.

They are worth $2.75, hence, considering the value of each coin(dimes $0.1 and quarters $0.25), we have that:

0.1x + 0.25y = 2.75

Since y = 14 - x:

0.1x + 0.25(14 - x) = 2.75

x = (0.25*14 - 2.75)/0.15.

x = 5.

y = 14 - x = 14 - 5 = 9.

There are 5 dimes and 9 quarters in his pocket.

More can be learned about a system of equations at brainly.com/question/24342899

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4 0
2 years ago
The difference between of two numbers is 9. If the large number is one more than twice the smaller number, find the larger numbe
sleet_krkn [62]

The larger number is 17

<em><u>Solution:</u></em>

Let "x" be the larger number

Let "y" be the smaller number

<em><u>The difference between of two numbers is 9</u></em>

Therefore,

larger number - smaller number = 9

x - y = 9 -------- eqn 1

<em><u>The large number is one more than twice the smaller number</u></em>

Larger number = 1 + 2(smaller number)

x = 1 + 2y ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

1 + 2y - y = 9

1 + y = 9

y = 9 - 1

y = 8

<em><u>Substitute y = 8 in eqn 1</u></em>

x - 8 = 9

x = 8 + 9

x = 17

Thus the larger number is 17

6 0
3 years ago
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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