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SIZIF [17.4K]
3 years ago
11

Express as an ordinary number. 6.983 x 10^4

Mathematics
1 answer:
fredd [130]3 years ago
4 0

Answer: 69,830

Step-by-step explanation: you basically move the decimal to the right for positive left for negitive and move as many places as the power of the exponent

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Determine the quotient: 2 4/7 ÷ 1 3/6
Scilla [17]

First we must change these numbers to improper fractions:

2\frac{4}{7}=\frac{18}{7}

1\frac{3}{6}=\frac{9}{6}

So then we set it up:

\frac{18}{7} ÷ \frac{9}{6}

When we divide fractions like this, we must flip the second fraction and change the sign from division to multiplication like so:

\frac{18}{7}*\frac{6}{9}

Then we solve:

\frac{108}{63}

Then if we divide the numerator and the denominator by 9, we get:

\frac{12}{7} or, in mixed-number form, 1\frac{5}{7}.

4 0
3 years ago
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

I=sen(t)-t.cos(t)+C

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

cos(t)=\sqrt{1-sen^2(t)}

Entonces:

cos(t)=\sqrt{1-x^2}

Devolviendo los cambios:

I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C

Es la respuesta correcta

7 0
3 years ago
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Plug 8 into the equation and divide it by that equation but with 5 plugged in

\frac{ {8}^{2} + 6(8) + 11}{ {5}^{2} + 6(5) + 11 }
6 0
3 years ago
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scoundrel [369]
The answer is 9 3/8 :)
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3 years ago
How would you factor 12b^4+3b^2​
Alex777 [14]

Answer:

3b²(4b²+1)

Step-by-step explanation:

You can factor out a 3b²

3b²(4b²+1)

7 0
2 years ago
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