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3 years ago

What is the approximate volume of the cone with a height of 9 cm and a radius of 15 cm.

1 answer:

7 0

The volume of a cone is pi multiplied by the radius squared times the height divided by three.

If 3.14 is used for pi:
V = 3.14 * 15^2 (9/3)
= 3.14 * 15^2 (3)
= 3.14 * 225 * 3
= 706.5 * 3
= 2,119.5 cm cubed

If 3.14 is not used for pi:
<span>V = pi * 15^2 (9/3)
</span> = pi * 15^2 (3)
= pi * 225 * 3
= 706.8583470577035 * 3
= 2,120.57504117311 cm cubed

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Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

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Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

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$P(w)=\frac{2}{9}$

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Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

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